What is the carrier frequency in an AM wave when its highest frequency...
Upper frequency = 850Hz
Bandwidth = 50Hz
Therefore lower Frequency = 850 - 50= 800 Hz
Carrier Frequency = (850-800)/2
= 825 Hz
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What is the carrier frequency in an AM wave when its highest frequency...
Given:
Highest frequency component of the signal, fmax = 850 Hz
Bandwidth of the signal, B = 50 Hz
To find:
Carrier frequency of the AM wave, fc
Explanation:
In AM modulation, the carrier signal is modulated by the message signal to obtain the modulated signal. The carrier frequency is the frequency of the sinusoidal waveform that is used to carry the information. The message signal is usually a low-frequency signal, and it modulates the amplitude of the carrier signal.
The bandwidth of the AM signal is given by:
B = 2 × fmax
where fmax is the highest frequency component of the message signal.
We can rearrange this equation to find the highest frequency component of the message signal:
fmax = B/2
Substituting the given values, we get:
fmax = 50/2 = 25 Hz
The modulated signal has a bandwidth of 2B, which means that the frequency range of the modulated signal is from fc - B to fc + B. Therefore, the carrier frequency can be calculated as:
fc = fmax + B
Substituting the values, we get:
fc = 850 + 50 = 900 Hz
Therefore, the carrier frequency of the AM wave is 900 Hz.
Answer: Option D) 825 Hz
What is the carrier frequency in an AM wave when its highest frequency...
It's kinda simple question
Since, it's an AM-wave so Bandwidth=2×fm(frequency of message signal)
50 = 2 × fm
fm = 25
and since highest frequency component is 850 which is equal to (fc+fm) in AM wave
so, fc+fm=850
fc + 25 = 850
hence, fc = 825
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