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A train is travelling at a speed of 90km/hr. Brakes are applied so as to produce a uniform acceleration of -0.5m/s^2. Find how far will the train to before it is brought to rest?
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Calculating the distance for the train to stop
- First, convert the speed from km/hr to m/s:
- 90 km/hr = 25 m/s
- Next, calculate the time taken for the train to stop:
- Using the formula v = u + at, where v is the final velocity (0 m/s), u is the initial velocity (25 m/s), a is the acceleration (-0.5 m/s^2), and t is the time taken.
- 0 = 25 + (-0.5)t
- t = 25 / 0.5 = 50 seconds
- Finally, calculate the distance traveled by the train:
- Using the formula s = ut + (1/2)at^2, where s is the distance, u is the initial velocity, t is the time, and a is the acceleration.
- s = 25 * 50 + (1/2) * (-0.5) * (50)^2
- s = 1250 - 625 = 625 meters
Therefore, the train will travel 625 meters before it is brought to a stop.
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A train is travelling at a speed of 90km/hr. Brakes are applied so as to produce a uniform acceleration of -0.5m/s^2. Find how far will the train to before it is brought to rest?
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