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A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest?
Most Upvoted Answer
A train travelling at a speed of 90km/h.brakes are appplied so as to p...
Given
u = 90×5/18=25m/s
v=0m/s
a=-0.5m/S2
s=?
from equation of motion
2as=v2-u2
s=v2-u2/2a
= o-25×25/2×-0.5
= -625/-1
s = 625m
u = 90×5/18=25m/s
v=0m/s
a=-0.5m/S2
s=?
from equation of motion
2as=v2-u2
s=v2-u2/2a
= o-25×25/2×-0.5
= -625/-1
s = 625m
Community Answer
A train travelling at a speed of 90km/h.brakes are appplied so as to p...
Given:
- Initial speed (u) = 90 km/h
- Acceleration (a) = 0.5 m/s^2
To find:
- Distance covered by the train before coming to rest
Formula:
The formula used to calculate the distance covered by an object under uniform acceleration is:
s = (v^2 - u^2) / (2a)
Where,
- s is the distance covered
- v is the final velocity
- u is the initial velocity
- a is the acceleration
Conversion:
To use the formula, we need to convert the initial velocity from km/h to m/s.
Given:
- Initial velocity (u) = 90 km/h
Conversion:
1 km/h = 1000 m/3600 s (since 1 km = 1000 m and 1 hour = 3600 s)
So, 90 km/h = (90 × 1000) / 3600 m/s = 25 m/s
Calculating final velocity:
When the train comes to rest, the final velocity (v) will be 0 m/s.
Substituting the values in the formula:
s = (v^2 - u^2) / (2a)
s = (0^2 - 25^2) / (2 × 0.5)
s = (-625) / 1
s = -625 m
Answer:
The train will cover a distance of 625 meters before coming to rest.
- Initial speed (u) = 90 km/h
- Acceleration (a) = 0.5 m/s^2
To find:
- Distance covered by the train before coming to rest
Formula:
The formula used to calculate the distance covered by an object under uniform acceleration is:
s = (v^2 - u^2) / (2a)
Where,
- s is the distance covered
- v is the final velocity
- u is the initial velocity
- a is the acceleration
Conversion:
To use the formula, we need to convert the initial velocity from km/h to m/s.
Given:
- Initial velocity (u) = 90 km/h
Conversion:
1 km/h = 1000 m/3600 s (since 1 km = 1000 m and 1 hour = 3600 s)
So, 90 km/h = (90 × 1000) / 3600 m/s = 25 m/s
Calculating final velocity:
When the train comes to rest, the final velocity (v) will be 0 m/s.
Substituting the values in the formula:
s = (v^2 - u^2) / (2a)
s = (0^2 - 25^2) / (2 × 0.5)
s = (-625) / 1
s = -625 m
Answer:
The train will cover a distance of 625 meters before coming to rest.
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A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest?
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A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest?.
A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train travelling at a speed of 90km/h.brakes are appplied so as to produce a uniform acceleration of 0.5m/s.find how far the train will go before it is brought to rest?.
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