Class 12 Exam > Class 12 Questions > One gas bleaches the colour of flowers by red...
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One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively are
- a)SO2 and CI2
- b)CO2 and CI2
- c)NO and CI2
- d)H2S and Br2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
One gas bleaches the colour of flowers by reduction and another gas by...
Cl2 bleaches by oxidation while SO2 does it by reduction.
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One gas bleaches the colour of flowers by reduction and another gas by...
Gas Bleaching of Flowers by Reduction and Oxidation
Reduction and oxidation reactions play a crucial role in various chemical processes. In the context of bleaching the color of flowers, two gases are involved, one causing bleaching by reduction and the other by oxidation. Let us examine the given options to identify the correct gases.
Option A: SO2 and Cl2
Option B: CO2 and Cl2
Option C: NO and Cl2
Option D: H2S and Br2
Based on the given options, the correct gases are SO2 and Cl2.
Explanation:
1. Reduction and Oxidation Reactions:
Reduction is a process that involves the gain of electrons or a decrease in oxidation state, while oxidation is a process that involves the loss of electrons or an increase in oxidation state. In the context of bleaching, reduction and oxidation reactions are responsible for altering the color of flowers.
2. SO2 and Cl2:
Sulfur dioxide (SO2) is an example of a reducing agent. It can bleach the color of flowers by undergoing reduction reactions. SO2 is capable of reacting with pigments responsible for the color of flowers and reducing them, resulting in a loss of color.
Chlorine gas (Cl2), on the other hand, is an example of an oxidizing agent. It can bleach the color of flowers by undergoing oxidation reactions. Cl2 can react with pigments responsible for the color of flowers and oxidize them, leading to a loss of color.
Therefore, the correct answer is option A: SO2 and Cl2. SO2 acts as a reducing agent, while Cl2 acts as an oxidizing agent to bleach the color of flowers.
In summary, reduction and oxidation reactions are involved in bleaching the color of flowers. Sulfur dioxide (SO2) acts as a reducing agent, while chlorine gas (Cl2) acts as an oxidizing agent to bleach the color of flowers.
Reduction and oxidation reactions play a crucial role in various chemical processes. In the context of bleaching the color of flowers, two gases are involved, one causing bleaching by reduction and the other by oxidation. Let us examine the given options to identify the correct gases.
Option A: SO2 and Cl2
Option B: CO2 and Cl2
Option C: NO and Cl2
Option D: H2S and Br2
Based on the given options, the correct gases are SO2 and Cl2.
Explanation:
1. Reduction and Oxidation Reactions:
Reduction is a process that involves the gain of electrons or a decrease in oxidation state, while oxidation is a process that involves the loss of electrons or an increase in oxidation state. In the context of bleaching, reduction and oxidation reactions are responsible for altering the color of flowers.
2. SO2 and Cl2:
Sulfur dioxide (SO2) is an example of a reducing agent. It can bleach the color of flowers by undergoing reduction reactions. SO2 is capable of reacting with pigments responsible for the color of flowers and reducing them, resulting in a loss of color.
Chlorine gas (Cl2), on the other hand, is an example of an oxidizing agent. It can bleach the color of flowers by undergoing oxidation reactions. Cl2 can react with pigments responsible for the color of flowers and oxidize them, leading to a loss of color.
Therefore, the correct answer is option A: SO2 and Cl2. SO2 acts as a reducing agent, while Cl2 acts as an oxidizing agent to bleach the color of flowers.
In summary, reduction and oxidation reactions are involved in bleaching the color of flowers. Sulfur dioxide (SO2) acts as a reducing agent, while chlorine gas (Cl2) acts as an oxidizing agent to bleach the color of flowers.
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One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively area)SO2 and CI2b)CO2 and CI2c)NO and CI2d)H2Sand Br2Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively area)SO2 and CI2b)CO2 and CI2c)NO and CI2d)H2Sand Br2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively area)SO2 and CI2b)CO2 and CI2c)NO and CI2d)H2Sand Br2Correct answer is option 'A'. Can you explain this answer?.
One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively area)SO2 and CI2b)CO2 and CI2c)NO and CI2d)H2Sand Br2Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively area)SO2 and CI2b)CO2 and CI2c)NO and CI2d)H2Sand Br2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively area)SO2 and CI2b)CO2 and CI2c)NO and CI2d)H2Sand Br2Correct answer is option 'A'. Can you explain this answer?.
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