Explanation:

To understand why the correct answer is option 'A' (NAND gate), let's break down the question and analyze the given information.

The question states that a signal passing through a gate is inhibited by sending a LOW into one of the inputs, and as a result, the output is HIGH. Based on this information, we can eliminate options 'B' (AND) and 'D' (OR) because these gates only output a HIGH signal if all their inputs are HIGH. In this case, one of the inputs is LOW, so these gates cannot produce a HIGH output.

Now let's consider option 'C' (NOR) and option 'A' (NAND).

NOR Gate:
A NOR gate produces a HIGH output only when both of its inputs are LOW. In this case, we are told that sending a LOW into one of the inputs inhibits the signal and the output is HIGH. This contradicts the behavior of a NOR gate because for a NOR gate to produce a HIGH output, both inputs must be LOW. Therefore, option 'C' can be eliminated.

NAND Gate:
A NAND gate produces a LOW output only when all of its inputs are HIGH. In this case, we are told that sending a LOW into one of the inputs inhibits the signal and the output is HIGH. This behavior aligns with a NAND gate because if one of the inputs is LOW, the output will be HIGH regardless of the state of the other input. Therefore, option 'A' (NAND) is the correct answer.

Summary:
Based on the given information, the gate that inhibits the signal by sending a LOW into one of the inputs and produces a HIGH output is a NAND gate. It is important to understand the behavior and truth tables of different logic gates to correctly identify their functionality.