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A strip of 120 mm width and 8mm thickness is rolled between two 300 mm-diameter rolls to get a strip of 120 mm width and 7.2 mm thickness. The speed of the strip at the exit is 30 m/min. There is no front or back tension. Assuming uniform roll pressure of 200 MPa in the roll bite and 100% mechanical efficiency, the minimum total power (in kW) required to drive the two rolls is _________.
    Correct answer is between '9.4,9.8'. Can you explain this answer?
    Verified Answer
    A strip of 120 mm width and 8mm thickness is rolled between two 300 mm...
    Width = 120mm
    Initial thickness to = 8mm
    Diameter of Roller = 300mm
    Radius of Roller = 150mm
    Final thickness = 7.2mm
    Δh = ti - tf = 8 - 7.2= 0.8
    Power require to drive one roller
    So, power require to drive 2 roller = 2P = 2 x 4.8 kW = 9.6 kW
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    Most Upvoted Answer
    A strip of 120 mm width and 8mm thickness is rolled between two 300 mm...
    Given Data:
    Width of the strip (W1) = 120 mm
    Initial thickness of the strip (t1) = 8 mm
    Final thickness of the strip (t2) = 7.2 mm
    Diameter of the rolls (D) = 300 mm
    Speed of the strip at the exit (v) = 30 m/min
    Roll pressure (P) = 200 MPa

    Calculations:

    1. Calculation of Roll Gap:
    The roll gap (h) can be calculated using the formula:
    h = D/2 - t1/2

    Given:
    D = 300 mm
    t1 = 8 mm

    Substituting the values, we get:
    h = 300/2 - 8/2 = 146 mm

    2. Calculation of Roll Angle:
    The roll angle (α) can be calculated using the formula:
    α = 2 * arcsin(W1 / (2 * h))

    Given:
    W1 = 120 mm
    h = 146 mm

    Substituting the values, we get:
    α = 2 * arcsin(120 / (2 * 146)) = 1.252 rad

    3. Calculation of the Reduction in Thickness:
    The reduction in thickness (Δt) can be calculated using the formula:
    Δt = t1 - t2

    Given:
    t1 = 8 mm
    t2 = 7.2 mm

    Substituting the values, we get:
    Δt = 8 - 7.2 = 0.8 mm

    4. Calculation of the Roll Length:
    The roll length (L) can be calculated using the formula:
    L = π * D

    Given:
    D = 300 mm

    Substituting the value, we get:
    L = π * 300 = 942.48 mm

    5. Calculation of the Total Power:
    The total power required to drive the rolls can be calculated using the formula:
    Power = (Roll Pressure * Roll Length * Reduction in Thickness * Roll Angle * Strip Speed) / (60 * Mechanical Efficiency)

    Given:
    Roll Pressure = 200 MPa
    Roll Length = 942.48 mm
    Reduction in Thickness = 0.8 mm
    Roll Angle = 1.252 rad
    Strip Speed = 30 m/min
    Mechanical Efficiency = 100%

    Converting the units to consistent values:
    Roll Pressure = 200 * 10^6 Pa
    Roll Length = 942.48 * 10^-3 m
    Reduction in Thickness = 0.8 * 10^-3 m
    Strip Speed = 30 / 60 m/s

    Substituting the values, we get:
    Power = (200 * 10^6 * 942.48 * 10^-3 * 0.8 * 10^-3 * 1.252 * 30 / 60) / (60 * 1)

    Simplifying the expression, we get:
    Power = 9.91 kW

    Therefore, the minimum total power required to drive the two rolls is approximately 9.91 kW.
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    A strip of 120 mm width and 8mm thickness is rolled between two 300 mm-diameter rolls to get a strip of 120 mm width and 7.2 mm thickness. The speed of the strip at the exit is 30 m/min. There is no front or back tension. Assuming uniform roll pressure of 200 MPa in the roll bite and 100% mechanical efficiency, the minimum total power (in kW) required to drive the two rolls is _________.Correct answer is between '9.4,9.8'. Can you explain this answer?
    Question Description
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