Mechanical Engineering Exam > Mechanical Engineering Questions > A thin cylindrical shell of 500 mm diameter ...
Start Learning for Free
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)
Correct answer is '19.23'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A thin cylindrical shell of 500 mm diameter is required to withstand ...
Problem:
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)
Solution:
To determine the minimum thickness of the cylindrical shell, we need to consider the following factors:
1. Stress due to internal pressure
2. Factor of safety
3. Efficiency of the joint
1. Stress due to internal pressure:
The stress due to internal pressure is given by the formula:
Stress = Internal Pressure x Radius / Thickness
Here, the internal pressure is 5 N/mm2 and the radius is 250 mm (half of the diameter). Let the thickness of the cylindrical shell be t.
Therefore, Stress = 5 x 250 / t
Stress = 1250 / t N/mm2
2. Factor of safety:
The factor of safety is given as 4.
3. Efficiency of the joint:
The efficiency of the joint is given as 65%. This means that only 65% of the material strength can be utilized.
Now, to determine the minimum thickness of the cylindrical shell, we need to ensure that the stress due to internal pressure is less than or equal to the allowable stress.
The allowable stress is given by the formula:
Allowable Stress = Maximum Tensile Strength x Efficiency of Joint / Factor of Safety
Here, the maximum tensile strength is 400 N/mm2, the efficiency of the joint is 65%, and the factor of safety is 4.
Therefore, Allowable Stress = 400 x 0.65 / 4
Allowable Stress = 65 N/mm2
Now, equating the stress due to internal pressure and the allowable stress, we get:
1250 / t = 65
t = 1250 / 65
t = 19.23 mm (rounded to two decimal places)
Therefore, the minimum thickness of the cylindrical shell is 19.23 mm.
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)
Solution:
To determine the minimum thickness of the cylindrical shell, we need to consider the following factors:
1. Stress due to internal pressure
2. Factor of safety
3. Efficiency of the joint
1. Stress due to internal pressure:
The stress due to internal pressure is given by the formula:
Stress = Internal Pressure x Radius / Thickness
Here, the internal pressure is 5 N/mm2 and the radius is 250 mm (half of the diameter). Let the thickness of the cylindrical shell be t.
Therefore, Stress = 5 x 250 / t
Stress = 1250 / t N/mm2
2. Factor of safety:
The factor of safety is given as 4.
3. Efficiency of the joint:
The efficiency of the joint is given as 65%. This means that only 65% of the material strength can be utilized.
Now, to determine the minimum thickness of the cylindrical shell, we need to ensure that the stress due to internal pressure is less than or equal to the allowable stress.
The allowable stress is given by the formula:
Allowable Stress = Maximum Tensile Strength x Efficiency of Joint / Factor of Safety
Here, the maximum tensile strength is 400 N/mm2, the efficiency of the joint is 65%, and the factor of safety is 4.
Therefore, Allowable Stress = 400 x 0.65 / 4
Allowable Stress = 65 N/mm2
Now, equating the stress due to internal pressure and the allowable stress, we get:
1250 / t = 65
t = 1250 / 65
t = 19.23 mm (rounded to two decimal places)
Therefore, the minimum thickness of the cylindrical shell is 19.23 mm.
Free Test
FREE
| Start Free Test |
Community Answer
A thin cylindrical shell of 500 mm diameter is required to withstand ...
Given data: d = 500 mm, P = 5 N/mm2
Syt = 400 N/mm2 , FOS = 4
∴ Allowable stress = = Syt/FOS = 400/4 = 100 N/mm2
For minimum thickness,
Pd/2tη = 100 N/mm2
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer?
Question Description
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer?.
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer?.
Solutions for A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer?, a detailed solution for A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? has been provided alongside types of A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A thin cylindrical shell of 500 mm diameter is required to withstand an internal fluid pressure of 5 N/mm2. IF the maximum tensile strength of plate material is 400 N/mm2 and efficiency of the joint is 65%, the minimum thickness (in mm) of the cylindrical shell by considering factor of safety of 4 is_______ . (Rounded to two decimal places)Correct answer is '19.23'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup