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A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held between two rigid supports as shown in figure. An internal pressure of 5 N/mm2 is applied on the inner surface of the cylinder. The resultant axial stresses developed in the cylinder (μ = 0.35) is _________MPa
(A) 21.0
(B) 22.5
    Correct answer is option ''. Can you explain this answer?
    Verified Answer
    A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held b...
    Stresses developed
    σc = = 62.5 N/mm2
    σa = = 31.25 N/mm2
    Due to rigid end supports, axial strain, εa = 0 Say σa′ is axial compressive stress provided by rigid end supports.
    Resultant axial stress, σaR = 31.25 − σa
    Axial strain, εa = = 0
    Or 31.25 − σa′ − 0.35(62.5) = 0
    σa′ = 31.25 − 21.875
    = 9.375 N/mm2
    Resultant axial stress, σaR = 31.25 − 9.375 = 21.875 N/mm2
    Question_Type: 5
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    Most Upvoted Answer
    A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held b...
    If u observer because of longitudinal steess it will tend to act along the lenght but because of rigid support it won't be able to elongate so the support must be acting certain stress in that direction. Fixed ex=0
    SigmaL/e-(u sigmah/e) =0
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    Community Answer
    A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held b...
    Stresses developed
    σc = = 62.5 N/mm2
    σa = = 31.25 N/mm2
    Due to rigid end supports, axial strain, εa = 0 Say σa′ is axial compressive stress provided by rigid end supports.
    Resultant axial stress, σaR = 31.25 − σa
    Axial strain, εa = = 0
    Or 31.25 − σa′ − 0.35(62.5) = 0
    σa′ = 31.25 − 21.875
    = 9.375 N/mm2
    Resultant axial stress, σaR = 31.25 − 9.375 = 21.875 N/mm2
    Question_Type: 5
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    A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held between two rigid supports as shown in figure. An internal pressure of 5 N/mm2 is applied on the inner surface of the cylinder. The resultant axial stresses developed in the cylinder (μ = 0.35) is _________MPa(A) 21.0(B) 22.5Correct answer is option ''. Can you explain this answer?
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    A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held between two rigid supports as shown in figure. An internal pressure of 5 N/mm2 is applied on the inner surface of the cylinder. The resultant axial stresses developed in the cylinder (μ = 0.35) is _________MPa(A) 21.0(B) 22.5Correct answer is option ''. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held between two rigid supports as shown in figure. An internal pressure of 5 N/mm2 is applied on the inner surface of the cylinder. The resultant axial stresses developed in the cylinder (μ = 0.35) is _________MPa(A) 21.0(B) 22.5Correct answer is option ''. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin cylindrical shell of diameter 200 mm, thickness 8 mm is held between two rigid supports as shown in figure. An internal pressure of 5 N/mm2 is applied on the inner surface of the cylinder. The resultant axial stresses developed in the cylinder (μ = 0.35) is _________MPa(A) 21.0(B) 22.5Correct answer is option ''. Can you explain this answer?.
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