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A machine component made of a ductile material is subjected to a variable loading with
σmin = -50 MPa and σmax = 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σ
σmin = -50 MPa and σmax = 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σ
y
= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer?
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Verified Answer
A machine component made of a ductile material is subjected to a varia...
σmax = 50MPa
σmin = -50MPa
σy = 300MPa
σe = 100MPa
Most Upvoted Answer
A machine component made of a ductile material is subjected to a varia...
The factor of safety (FS) is a measure of how much a component can withstand a certain load compared to its expected strength. It is calculated by dividing the yield strength of the material by the maximum stress experienced by the component. In this case, we are given the corrected endurance limit (e) and the yield strength (y) of the material.
Calculating the maximum stress:
The maximum stress experienced by the component is the maximum value of the variable loading, which is 50 MPa.
Calculating the factor of safety:
The factor of safety can be calculated using the formula:
FS = y / max stress
Substituting the given values:
FS = 300 MPa / 50 MPa = 6
However, this value does not fall within the given range of '1.99,2.01'. This suggests that there might be a correction factor that needs to be taken into account.
Considering the corrected endurance limit:
The corrected endurance limit (e) is the maximum stress that a component can withstand for an infinite number of cycles without failure. It takes into account factors such as stress concentration, surface finish, and material quality.
The corrected endurance limit can be used to calculate the corrected factor of safety (FS') using the formula:
FS' = e / max stress
Substituting the given values:
FS' = 100 MPa / 50 MPa = 2
This value falls within the given range of '1.99,2.01', indicating that the corrected factor of safety is the desired answer.
Concluding the answer:
The factor of safety is a measure of the safety margin of a component. In this case, the corrected factor of safety is 2, which means that the component can withstand twice the maximum stress it is subjected to. This provides a reasonable safety margin for the component and ensures that it will not fail under the given loading conditions.
It is important to note that the corrected endurance limit is used instead of the yield strength in this calculation because the variable loading can cause fatigue failure rather than yielding of the material. Taking into account the correct endurance limit provides a more accurate measure of the component's safety.
Calculating the maximum stress:
The maximum stress experienced by the component is the maximum value of the variable loading, which is 50 MPa.
Calculating the factor of safety:
The factor of safety can be calculated using the formula:
FS = y / max stress
Substituting the given values:
FS = 300 MPa / 50 MPa = 6
However, this value does not fall within the given range of '1.99,2.01'. This suggests that there might be a correction factor that needs to be taken into account.
Considering the corrected endurance limit:
The corrected endurance limit (e) is the maximum stress that a component can withstand for an infinite number of cycles without failure. It takes into account factors such as stress concentration, surface finish, and material quality.
The corrected endurance limit can be used to calculate the corrected factor of safety (FS') using the formula:
FS' = e / max stress
Substituting the given values:
FS' = 100 MPa / 50 MPa = 2
This value falls within the given range of '1.99,2.01', indicating that the corrected factor of safety is the desired answer.
Concluding the answer:
The factor of safety is a measure of the safety margin of a component. In this case, the corrected factor of safety is 2, which means that the component can withstand twice the maximum stress it is subjected to. This provides a reasonable safety margin for the component and ensures that it will not fail under the given loading conditions.
It is important to note that the corrected endurance limit is used instead of the yield strength in this calculation because the variable loading can cause fatigue failure rather than yielding of the material. Taking into account the correct endurance limit provides a more accurate measure of the component's safety.
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A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer?
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A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer?.
A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A machine component made of a ductile material is subjected to a variable loading withσmin= -50 MPa and σmax= 50 MPa. If the corrected endurance limit and the yield strength for the material are σe= 100 MPa and σy= 300MPa, the factor of safety is __________Correct answer is between '1.99,2.01'. Can you explain this answer?.
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