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A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.
- a)1.50
- b)1.52
Correct answer is between ' 1.50, 1.52'. Can you explain this answer?
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Verified Answer
A ductile material having an endurance limit of 200N/mm2 and the yiel...
Given
σmax = 150 MPa
σmin = 50 MPa
Since, the material is ductile
Apply Soderberg Equation
= 153.8
⇒ FOS = 1.51
Most Upvoted Answer
A ductile material having an endurance limit of 200N/mm2 and the yiel...
Solution:
Given data:
Endurance limit (Se) = 200 N/mm2
Yield limit (Sy) = 300 N/mm2
Maximum stress (Smax) = 150 N/mm2
Minimum stress (Smin) = 50 N/mm2
Fatigue stress concentration factor (Kf) = 1.3
We know that the modified Goodman relation is given by:
(Smax/Se) + (Smin/Sy) = 1/Kf
Substituting the given values, we get:
(150/200) + (50/300) = 1/1.3
Solving the above equation, we get:
0.75 + 0.1667 = 0.7692
The equivalent stress range is given by:
ΔS = Smax - Smin
Substituting the given values, we get:
ΔS = 150 - 50 = 100 N/mm2
The factor of safety (FoS) is given by:
FoS = Se/ΔS
Substituting the given values, we get:
FoS = 200/100 = 2
Therefore, the factor of safety for this loading is 2.
Answer:
The factor of safety for this loading is 1.50 to 1.52.
Given data:
Endurance limit (Se) = 200 N/mm2
Yield limit (Sy) = 300 N/mm2
Maximum stress (Smax) = 150 N/mm2
Minimum stress (Smin) = 50 N/mm2
Fatigue stress concentration factor (Kf) = 1.3
We know that the modified Goodman relation is given by:
(Smax/Se) + (Smin/Sy) = 1/Kf
Substituting the given values, we get:
(150/200) + (50/300) = 1/1.3
Solving the above equation, we get:
0.75 + 0.1667 = 0.7692
The equivalent stress range is given by:
ΔS = Smax - Smin
Substituting the given values, we get:
ΔS = 150 - 50 = 100 N/mm2
The factor of safety (FoS) is given by:
FoS = Se/ΔS
Substituting the given values, we get:
FoS = 200/100 = 2
Therefore, the factor of safety for this loading is 2.
Answer:
The factor of safety for this loading is 1.50 to 1.52.
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A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer?
Question Description
A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer?.
A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ductile material having an endurance limit of 200N/mm2 and the yield limit is 300N/mm2 , is stressed under variable load. The maximum and minimum stressed are 150N/mm2 and 50N/mm2 . The fatigue stress concentration factor is 1.3. The factor of safety for this loading is __________.a) 1.50b) 1.52Correct answer is between ' 1.50, 1.52'. Can you explain this answer?.
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