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The sum of currents entering a junction is 9 A. If the current leaves the junction form 3 different paths having the same resistance, the current leaving from any one of the path will be:
- a)1 A
- b)9 A
- c)3 A
- d)It cannot be determined
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The sum of currents entering a junction is 9 A. If the current leaves ...
By KCL,
The sum of current entering a junction is equal to the sum of current leaving at that junction.
⇒ Sum of currents leaving = 9 A
This 9 A current will flow through three resistances having same value.
The current will be some through each resistor
Most Upvoted Answer
The sum of currents entering a junction is 9 A. If the current leaves ...
Introduction:
In electrical circuits, current is the flow of electric charge. At a junction, the sum of currents entering the junction is equal to the sum of currents leaving the junction. This principle is known as Kirchhoff's Current Law (KCL).
Given:
- Sum of currents entering the junction = 9 A
Explanation:
When the current leaves the junction and flows through different paths, it is important to note that the sum of currents leaving the junction will also be equal to the sum of currents entering the junction.
Let's assume that the current leaving the junction through each path is I.
Analysis:
If the current leaves the junction through 3 different paths, and all paths have the same resistance, then the current through each path will be equal. This can be explained using Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance.
Since the resistance is the same for all paths, the voltage across each path will also be the same. Therefore, according to Ohm's Law, the current through each path will be the same.
Conclusion:
Based on Kirchhoff's Current Law and Ohm's Law, we can conclude that the current leaving from any one of the paths will be equal to the sum of currents entering the junction divided by the number of paths.
In this case, the sum of currents entering the junction is 9 A, and there are 3 paths. Therefore, the current leaving from any one of the paths will be 9 A / 3 = 3 A.
Hence, the correct answer is option C - 3 A.
In electrical circuits, current is the flow of electric charge. At a junction, the sum of currents entering the junction is equal to the sum of currents leaving the junction. This principle is known as Kirchhoff's Current Law (KCL).
Given:
- Sum of currents entering the junction = 9 A
Explanation:
When the current leaves the junction and flows through different paths, it is important to note that the sum of currents leaving the junction will also be equal to the sum of currents entering the junction.
Let's assume that the current leaving the junction through each path is I.
Analysis:
If the current leaves the junction through 3 different paths, and all paths have the same resistance, then the current through each path will be equal. This can be explained using Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance.
Since the resistance is the same for all paths, the voltage across each path will also be the same. Therefore, according to Ohm's Law, the current through each path will be the same.
Conclusion:
Based on Kirchhoff's Current Law and Ohm's Law, we can conclude that the current leaving from any one of the paths will be equal to the sum of currents entering the junction divided by the number of paths.
In this case, the sum of currents entering the junction is 9 A, and there are 3 paths. Therefore, the current leaving from any one of the paths will be 9 A / 3 = 3 A.
Hence, the correct answer is option C - 3 A.
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The sum of currents entering a junction is 9 A. If the current leaves the junction form 3 different paths having the same resistance, the current leaving from any one of the path will be:a)1 Ab)9 Ac)3 Ad)It cannot be determinedCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The sum of currents entering a junction is 9 A. If the current leaves the junction form 3 different paths having the same resistance, the current leaving from any one of the path will be:a)1 Ab)9 Ac)3 Ad)It cannot be determinedCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of currents entering a junction is 9 A. If the current leaves the junction form 3 different paths having the same resistance, the current leaving from any one of the path will be:a)1 Ab)9 Ac)3 Ad)It cannot be determinedCorrect answer is option 'C'. Can you explain this answer?.
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