What is the median of first 9 multiples of 12?a)36b)48c)60d)72Correct ...
First 9 multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96, 108
n = 9

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What is the median of first 9 multiples of 12?a)36b)48c)60d)72Correct ...
Understanding the Problem
To find the median of the first 9 multiples of 12, we first need to identify what these multiples are.
First 9 Multiples of 12
- The multiples are calculated as:
1 × 12 = 12
2 × 12 = 24
3 × 12 = 36
4 × 12 = 48
5 × 12 = 60
6 × 12 = 72
7 × 12 = 84
8 × 12 = 96
9 × 12 = 108
- Therefore, the first 9 multiples of 12 are:
12, 24, 36, 48, 60, 72, 84, 96, 108
Finding the Median
- To find the median:
1. Arrange the numbers in ascending order (which they already are).
2. Since there are 9 numbers (an odd count), the median is the middle number.
- In this case, the middle number is the 5th number in the list.
Identifying the Middle Number
- The 5th multiple in the list is:
12, 24, 36, 48, 60, 72, 84, 96, 108
- Therefore, the median is 60.
Conclusion
- The median of the first 9 multiples of 12 is 60.
- Hence, the correct answer is option C.
What is the median of first 9 multiples of 12?a)36b)48c)60d)72Correct ...
To find the median of the first 9 multiples of 12, we need to list them:
1. 12
2. 24
3. 36
4. 48
5. 60
6. 72
7. 84
8. 96
9. 108
Since there are an odd number of values (9), the middle value is the median.
Median = 5th value = 60
So, the median of the first 9 multiples of 12 is 60.