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In a ∆ABC, ∠A – ∠B = 33° and ∠B – ∠C = 18°, then ∠B = ?
  • a)
    35°
  • b)
    55°
  • c)
    45°
  • d)
    57° 
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In a ∆ABC,∠A –∠B = 33° and ∠B –∠...
∠A = 33° + ∠B and ∠C = ∠B – 18°
∴ (33° + ∠B) + ∠B + (∠B – 18°) = 180° 
⇒ 3∠B = 165° 17. (d) ⇒ ∠B = 55°
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In a ∆ABC,∠A –∠B = 33° and ∠B –∠C= 18°, then ∠B = ?a)35°b)55°c)45°d)57°Correct answer is option 'B'. Can you explain this answer?
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