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The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%
- a)Rs. 158005.5
- b)Rs. 163005.5
- c)Rs.153300
- d)Rs.168005.5
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The average motor load of a consumer is 250 kW at a power factor 0.85 ...
Consumer motor load = 250 kW
Maximum demand = 250/0.85 = 294.11
Unit consumed per year = maximum demand × load factor × hours in a year
= 250 × 0.7 × 8760 = 1533000 kWh
Annual bill = Max demand charges + energy charges
= (294.11 × 50) + (1533000 × 0.1) = Rs. 168005.5
Most Upvoted Answer
The average motor load of a consumer is 250 kW at a power factor 0.85 ...
First, we need to calculate the apparent power (kVA) of the motor load. The formula for apparent power is:
Apparent Power (kVA) = Real Power (kW) / Power Factor
Apparent Power = 250 kW / 0.85 = 294.12 kVA
Next, we need to calculate the maximum demand charge. The maximum demand charge is based on the maximum apparent power used during a billing cycle. In this case, the maximum demand charge is calculated as:
Maximum Demand Charge = Maximum Apparent Power (kVA) * Tariff Rate (Rs./kVA)
Let's assume the maximum apparent power is 300 kVA and the tariff rate is Rs.50/kVA.
Maximum Demand Charge = 300 kVA * Rs.50/kVA = Rs.15,000
Finally, we need to calculate the energy charge. The energy charge is based on the actual units of electricity consumed during a billing cycle. In this case, the energy charge is calculated as:
Energy Charge = Units Consumed * Tariff Rate (Rs./unit)
Let's assume the consumer has consumed 1000 units and the tariff rate is 10 paise per unit.
Energy Charge = 1000 units * Rs.0.10/unit = Rs.100
Therefore, the total charge for the consumer would be the sum of the maximum demand charge and the energy charge:
Total Charge = Maximum Demand Charge + Energy Charge
Total Charge = Rs.15,000 + Rs.100
Total Charge = Rs.15,100
Apparent Power (kVA) = Real Power (kW) / Power Factor
Apparent Power = 250 kW / 0.85 = 294.12 kVA
Next, we need to calculate the maximum demand charge. The maximum demand charge is based on the maximum apparent power used during a billing cycle. In this case, the maximum demand charge is calculated as:
Maximum Demand Charge = Maximum Apparent Power (kVA) * Tariff Rate (Rs./kVA)
Let's assume the maximum apparent power is 300 kVA and the tariff rate is Rs.50/kVA.
Maximum Demand Charge = 300 kVA * Rs.50/kVA = Rs.15,000
Finally, we need to calculate the energy charge. The energy charge is based on the actual units of electricity consumed during a billing cycle. In this case, the energy charge is calculated as:
Energy Charge = Units Consumed * Tariff Rate (Rs./unit)
Let's assume the consumer has consumed 1000 units and the tariff rate is 10 paise per unit.
Energy Charge = 1000 units * Rs.0.10/unit = Rs.100
Therefore, the total charge for the consumer would be the sum of the maximum demand charge and the energy charge:
Total Charge = Maximum Demand Charge + Energy Charge
Total Charge = Rs.15,000 + Rs.100
Total Charge = Rs.15,100
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The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer?
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The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer?.
The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average motor load of a consumer is 250 kW at a power factor 0.85 lag. The consumer is charged electricity at the tariff of Rs.50/kVA of maximum demand plus 10 paise per unit consumed. Determine the consumer’s annual bill for a load factor of 70%a)Rs. 158005.5b)Rs. 163005.5c)Rs.153300d)Rs.168005.5Correct answer is option 'D'. Can you explain this answer?.
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