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Direction (Q. No. 14) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.
  • a)
    a
  • b)
    b
  • c)
    c
  • d)
    d
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Direction (Q. No. 14) Choices for the correct combination of elements ...
For 2nd graph half live is cons.on increasing conc.so it is of 1st order
for 1st graph rate remains cons.with time means independent on conc.so it is of 0 order
so ans.is c
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Community Answer
Direction (Q. No. 14) Choices for the correct combination of elements ...
(i) Rate remains constant
(dx/dt) = k(A)n = [A]0 = k
Thus   order = 0
Thus,(i)→(s)
(ii) Half-life period is independent of concentration
∴  (n-1) = 0
∴  n = 1
Thus, (ii) →(r)



Thus, graph is for second-order reactions
Thus, (iii) → (q)
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