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A resistor immersed in running water carries an electric current. Consider the resistor as the system.
Select one or more:
  • a)
    W = –ve, ΔU = –ve
  • b)
    W = –ve, ΔU = +ve
  • c)
    Q = 0
  • d)
    W = +ve, ΔU = +ve
Correct answer is option 'B,C'. Can you explain this answer?
Verified Answer
A resistor immersed in running water carries an electric current. Cons...
There is no flow of heat into the resistor and work is done on the resistor (system).
According to first law as applied to the system, we write,
ΔU = Q – W
For resistor Q = 0
W = –ve. Thus
ΔU = 0 – (–W) = W
∴ Q = 0; W = –ve, ΔU = +ve
The correct answers are: Q = 0, W = –ve, ΔU = +ve
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Most Upvoted Answer
A resistor immersed in running water carries an electric current. Cons...
The work done on the resistor by the running water.
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A resistor immersed in running water carries an electric current. Consider the resistor as the system.Select one or more:a)W = –ve, ΔU = –veb)W = –ve, ΔU = +vec)Q = 0d)W = +ve, ΔU = +veCorrect answer is option 'B,C'. Can you explain this answer?
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