All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  In which of the following case, increase in c... Start Learning for Free
In which of the following case, increase in concentration of ion cause increase in Ecell?
  • a)
    Pt(H2)|H+(Ag)
  • b)
    Ag,AgCl|Cl−(aq)
  • c)
    Pt|Quinhydrone|H+(aq
  • d)
    Ag|Ag+(aq)
Correct answer is option 'B'. Can you explain this answer?
Clear all your JEE doubts with EduRev
Verified Answer
In which of the following case, increase in concentration of ion cause...
View all questions of this test
Most Upvoted Answer
In which of the following case, increase in concentration of ion cause...
Explanation:
Increasing the concentration of ions can affect the cell potential in different types of electrochemical cells. Let's analyze the given cases to determine which one shows an increase in Ecell with an increase in ion concentration.

Case B: Ag, AgCl|Cl⁻(aq)
- In this case, the presence of Cl⁻ ions in the solution can react with AgCl to form more Ag+ ions, increasing their concentration.
- The reaction can be represented as: AgCl(s) ⇌ Ag+(aq) + Cl⁻(aq)
- As the concentration of Ag+ ions increases, the equilibrium of the cell reaction shifts to the right, increasing the cell potential (Ecell).
- Therefore, in this case, an increase in ion concentration causes an increase in Ecell.

Other Cases:
- Case A: Pt(H2)|H+(Ag) - This is a hydrogen electrode, and changing the H+ ion concentration does not affect the cell potential significantly.
- Case C: Pt|Quinhydrone|H+(aq) - The cell potential is determined by the redox reaction involving quinhydrone and is not directly influenced by the H+ ion concentration.
- Case D: Ag|Ag+(aq) - The cell potential is primarily determined by the Ag/Ag+ redox couple and is not significantly affected by the Ag+ ion concentration.
Therefore, the correct answer is option B, where an increase in ion concentration leads to an increase in Ecell.
Explore Courses for JEE exam

Similar JEE Doubts

There are many reactions which obey a first order rate equation although it reality they are bi- or ter-molecular. As an example of these may be taken the decomposition of Carbonyl sulfide in water, namely, COS + H20 002 + H2SAccording to the law of mass action this reaction should be second order with the rate dependent on the concentration of both the carbonyl sulfide and the water. Actually however, the rate is found to be first order with respect to the carbonyl sulfide and independent of the water Reactions exhibiting such behaviour are said to be pseudo-molecular.The pseudo-unimoecuar nature of this reaction is explainable by the fact that water is present in such excess that its concentration remains practically constant during the course of the reaction. Under these condition b x = b, and the rate equation becomesOn integration this leads towhich is the equation for a first order reaction. It is evident, however, that the now constant k is not independent of the concentration, as is the case with true first order constants, but may vary with b if the latter is changed appreciably, When such is the case, the true constant k2 can be obtained from k by dividing the latter by b. pseudo-molecular reactions are encountered whenever one or more of the reactants remain constants during the course of an experiment. This is the case with reactions conducted in solvents which are themselves one of the reactants, as in the decomposition of carbonyl sulfide in water, or in the esterification of acetic anhydride in alcohol(CH3C0)20 + 2C2H5OH 2CH3C00C2H5 + H20Again, this is also true of reactions subject to catalysis, in which case the concentration of the catalyst does not change. The decomposition of diacetone alcohol to acetone in aqueous solution is catalysed by hydroxyl ions, with the rate proportional to the concentration of the alcohol and that of the base. Since the concentration of the base does not change within any one experiment, however, the rate equation reduces to one of first order with respect to the alcohol. But the rateconstant k obtained for various concentrations of base are not identical, as may be seen from table. To obtain from these the true second order velocity constant, the ks must be divided by the hydroxyl ion concentration. When this is done excellent k2 values result, as column 3 indicatesTable : Decomposition of diacetone alcohol in water at 25C (Catalyst : NaOH)Q.By what factor does the rate of reaction of diacetone alcohol in water solution change if p0H is increased by 2 units other things remaining same ?

Top Courses for JEEView all

Top Courses for JEE

In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer?
Question Description
In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer?.
Solutions for In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In which of the following case, increase in concentration of ion cause increase inEcell?a)Pt(H2)|H+(Ag)b)Ag,AgCl|Cl−(aq)c)Pt|Quinhydrone|H+(aqd)Ag|Ag+(aq)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
SaveJoin the Discussion on the App for FREE
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup