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Following figure is for Q2-Q7.
AC= 1m, CB =3 m
C is just an arbitrary point. A is pin support and B is a roller type support.
Q. What will be the shear developed at point C if a uniform load of 10KN/m is applied between point B and C?
  • a)
    10.25 KN
  • b)
    11.25 KN
  • c)
    12.25 KN
  • d)
    13.25 KN
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Following figure is for Q2-Q7.AC= 1m, CB =3 mC is just an arbitrary po...
Answer: b
Explanation: In case of uniform load, area of ILD curve multiplied by uniform load gives the shear.
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Following figure is for Q2-Q7.AC= 1m, CB =3 mC is just an arbitrary point. A is pin support and B is a roller type support.Q. What will be the shear developed at point C if a uniform load of 10KN/m is applied between point B and C?a)10.25 KNb)11.25 KNc)12.25 KNd)13.25 KNCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Following figure is for Q2-Q7.AC= 1m, CB =3 mC is just an arbitrary point. A is pin support and B is a roller type support.Q. What will be the shear developed at point C if a uniform load of 10KN/m is applied between point B and C?a)10.25 KNb)11.25 KNc)12.25 KNd)13.25 KNCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Following figure is for Q2-Q7.AC= 1m, CB =3 mC is just an arbitrary point. A is pin support and B is a roller type support.Q. What will be the shear developed at point C if a uniform load of 10KN/m is applied between point B and C?a)10.25 KNb)11.25 KNc)12.25 KNd)13.25 KNCorrect answer is option 'B'. Can you explain this answer?.
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