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One or More than One Options Correct Type
This section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.
Q.
In the depression of freezing point experiment, it is found that the
  • a)
    vapour pressure of the solution is less than that of pure solvent
  • b)
     vapour pressure of the solution is more than that of pure solvent
  • c)
    only solute molecules solidify at the freezing poin
  • d)
     only solvent molecules solidify at the freezing point
Correct answer is option 'A,D'. Can you explain this answer?
Verified Answer
One or More than One Options Correct TypeThis section contains 2 multi...
(a, d) Liquid solvent   Solid solvent
Freezing point is the temperature at which liquid solvent and solid remain at equilibrium . In the following figure ,
On adding solute to solvent, vapour pressure falls p1 < p0 and T1<T0
Thus, (a) is correct.
Only solvent molecules solidify at the freezing point.
Thus, (d) is also correct.
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Most Upvoted Answer
One or More than One Options Correct TypeThis section contains 2 multi...
Depression of Freezing Point Experiment

In the depression of freezing point experiment, a solution is prepared by dissolving a solute in a solvent. The objective of this experiment is to measure the decrease in freezing point of the solvent caused by the presence of the solute.

Vapour Pressure of the Solution

The first statement states that the vapour pressure of the solution is less than that of the pure solvent. This statement is correct. When a solute is added to a solvent, the solute particles occupy some of the space between the solvent particles. This reduces the number of solvent particles available at the surface of the solution, leading to a decrease in the vapour pressure. Therefore, the vapour pressure of the solution is lower than that of the pure solvent.

Only Solute Molecules Solidify at the Freezing Point

The third statement states that only solute molecules solidify at the freezing point. This statement is incorrect. In a solution, both the solvent and solute molecules are present. When the temperature of the solution is lowered, the solvent molecules start to slow down and form a solid lattice at the freezing point. However, the presence of the solute disrupts the formation of this lattice and prevents the solvent molecules from solidifying. Therefore, it is incorrect to say that only solute molecules solidify at the freezing point.

Only Solvent Molecules Solidify at the Freezing Point

The fourth statement states that only solvent molecules solidify at the freezing point. This statement is correct. As mentioned earlier, when the temperature of the solution is lowered, the solvent molecules slow down and form a solid lattice at the freezing point. The solute particles do not participate in the solidification process and remain in the solution. Therefore, it is correct to say that only solvent molecules solidify at the freezing point.

Summary

To summarize, in the depression of freezing point experiment, the vapour pressure of the solution is lower than that of the pure solvent. Both the solvent and solute molecules are present in the solution, but only solvent molecules solidify at the freezing point. Therefore, the correct statements are option A (vapour pressure of the solution is less than that of pure solvent) and option D (only solvent molecules solidify at the freezing point).
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Read the following text and answer the following questions on the basis of the same:Microwave oven:The spectrum of electromagnetic radiation contains a part known as microwaves. These waves have frequency and energy smaller than visible light and wavelength larger than it. What is the principle of a microwave oven and how does it work ? Our objective is to cook food or warm it up. All food items such as fruit, vegetables, meat, cereals, etc., contain water as a constituent. Now, what does it mean when we say that a certain object has become warmer? When the temperature of a body rises, the energy of the random motion of atoms and molecules increases and the molecules travel or vibrate or rotate with higher energies. The frequency of rotation of water molecules is about 2.45 gigahertz (GHz). If water receives microwaves of this frequency, its molecules absorb this radiation, which is equivalent to heating up water. These molecules share this energy with neighbouring food molecules, heating up the food. One should use porcelain vessels and non metal containers in a microwave oven because of the danger of getting a shock from accumulated electric charges. Metals may also melt from heating. The porcelain container remains unaffected and cool, because its large molecules vibrate and rotate with much smaller frequencies, and thus cannot absorb microwaves. Hence, they do not get eaten up. Thus, the basic principle of a microwave oven is to generate microwave radiation of appropriate frequency in the working space of the oven where we keep food. This way energy is not wasted in heating up the vessel. In the conventional heating method, the vessel on the burner gets heated first and then the food inside gets heated because of transfer of energy from the vessel. In the microwave oven, on the other hand, energy is directly delivered to water molecules which are shared by the entire food.Q. As compared to visible light microwave has frequency and energy

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One or More than One Options Correct TypeThis section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.Q.In the depression of freezing point experiment, it is found that thea)vapour pressure of the solution is less than that of pure solventb)vapour pressure of the solution is more than that of pure solventc)only solute molecules solidify at the freezing poind)only solvent molecules solidify at the freezing pointCorrect answer is option 'A,D'. Can you explain this answer?
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One or More than One Options Correct TypeThis section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.Q.In the depression of freezing point experiment, it is found that thea)vapour pressure of the solution is less than that of pure solventb)vapour pressure of the solution is more than that of pure solventc)only solute molecules solidify at the freezing poind)only solvent molecules solidify at the freezing pointCorrect answer is option 'A,D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One or More than One Options Correct TypeThis section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.Q.In the depression of freezing point experiment, it is found that thea)vapour pressure of the solution is less than that of pure solventb)vapour pressure of the solution is more than that of pure solventc)only solute molecules solidify at the freezing poind)only solvent molecules solidify at the freezing pointCorrect answer is option 'A,D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One or More than One Options Correct TypeThis section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.Q.In the depression of freezing point experiment, it is found that thea)vapour pressure of the solution is less than that of pure solventb)vapour pressure of the solution is more than that of pure solventc)only solute molecules solidify at the freezing poind)only solvent molecules solidify at the freezing pointCorrect answer is option 'A,D'. Can you explain this answer?.
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