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Chlorobenzene on heating with NaOH at 300oC and high pressure followed by reaction with dil. HCl gives
  • a)
    Phenol
  • b)
    Benzaldehyde
  • c)
    Chlorophenol
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
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Chlorobenzene on heating with NaOH at 300oC and high pressure followed...
 
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Chlorobenzene on heating with NaOH at 300oC and high pressure followed...
Reaction:
Chlorobenzene (C6H5Cl) on heating with NaOH at 300oC and high pressure followed by reaction with dil. HCl gives phenol (C6H5OH).

Explanation:
The given reaction involves two steps:

1. Formation of sodium phenoxide:
Chlorobenzene reacts with NaOH (sodium hydroxide) at high temperature and pressure to form sodium phenoxide.

Equation:
C6H5Cl + NaOH → C6H5ONa + HCl

In this step, the chlorine atom of chlorobenzene is replaced by the sodium atom from NaOH, leading to the formation of sodium phenoxide.

2. Acidification to form phenol:
The sodium phenoxide formed in the first step is then treated with dilute hydrochloric acid (HCl) to yield phenol.

Equation:
C6H5ONa + HCl → C6H5OH + NaCl

In this step, the sodium phenoxide reacts with HCl, resulting in the displacement of the sodium ion by the hydrogen ion, leading to the formation of phenol.

Conclusion:
Therefore, the correct answer is option 'A' - Phenol (C6H5OH).
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Chlorobenzene on heating with NaOH at 300oC and high pressure followed by reaction with dil. HCl givesa)Phenolb)Benzaldehydec)Chlorophenold)None of theseCorrect answer is option 'A'. Can you explain this answer?
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