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Let Sn be the symmetry group of n letters and assume that it abelian. Then.
  • a)
    n = 1 or n = 2
  • b)
    n is a prime greater than 2
  • c)
    n is an even number greater than 2
  • d)
    n is an odd number greater than 2
Correct answer is option 'A'. Can you explain this answer?
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Let Sn be the symmetry group of n letters and assume that it abelian. ...
Group of symmetries S2n = { ....... r3, r2, r, e, f, fr, fr2 ......}
this group of symmetric is non-abelian for n ≥ 3 so if Sn be the symmetry group and it is abelian then n = 1 or n = 2.
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Let Sn be the symmetry group of n letters and assume that it abelian. ...
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Let Sn be the symmetry group of n letters and assume that it abelian. ...
Group of symmetries S2n = { ....... r3, r2, r, e, f, fr, fr2 ......}
this group of symmetric is non-abelian for n ≥ 3 so if Sn be the symmetry group and it is abelian then n = 1 or n = 2.
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Let Sn be the symmetry group of n letters and assume that it abelian. Then.a)n = 1 or n = 2b)n is a prime greater than 2c)n is an even number greater than 2d)n is an odd number greater than 2Correct answer is option 'A'. Can you explain this answer?
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