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Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 M nitric acid from it,
  • a)
    dilute 3.846 L of 15.6 M to 10.0 l solution
  • b)
    add 10.0 L H2O into 3.846 L of 15.6 M solution
  • c)
    add 3.846 L H2O into 6.154 L of 15.6 M solution
  • d)
    None of the above
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 ...
(a) This is a case of dilution.
Thus, 3.846 L of 15.6 M solution is diluted to 10.0 L by addition of 6.154 L of H20.
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Most Upvoted Answer
Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 ...
To prepare a 6.0 M nitric acid solution from a 15.6 M commercial concentrated nitric acid, we need to dilute the concentrated solution with water. Let's analyze the given options to determine the correct procedure:

a) Dilute 3.846 L of 15.6 M to 10.0 L solution
b) Add 10.0 L H2O into 3.846 L of 15.6 M solution
c) Add 3.846 L H2O into 6.154 L of 15.6 M solution
d) None of the above

To calculate the volume of concentrated nitric acid required, we can use the formula:

M1V1 = M2V2

Where:
M1 = initial concentration of nitric acid
V1 = initial volume of nitric acid
M2 = final concentration of nitric acid
V2 = final volume of nitric acid

Let's calculate the volume of concentrated nitric acid required to obtain a 6.0 M solution:

M1 = 15.6 M
V1 = ?
M2 = 6.0 M
V2 = 10.0 L

(15.6 M)(V1) = (6.0 M)(10.0 L)
V1 = (6.0 M)(10.0 L) / 15.6 M
V1 = 3.846 L

So, we need to dilute 3.846 L of the 15.6 M nitric acid solution to obtain a 6.0 M solution. This matches with option A.

Explanation:
- The formula M1V1 = M2V2 is used to calculate the volume of concentrated nitric acid required to prepare the desired solution.
- We substitute the known values into the formula and solve for V1, which gives us the volume of concentrated nitric acid required.
- Comparing the calculated volume with the given options, we can see that option A is the correct one.
- Option B suggests adding water to the concentrated solution, which would change the concentration and not give the desired 6.0 M concentration.
- Option C suggests adding water to a larger volume of the concentrated solution, which would also result in a different concentration.
- Therefore, the correct option is A, which involves diluting the concentrated solution to the desired volume of 10.0 L.
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Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 M nitric acid from it,a)dilute 3.846 L of 15.6 M to 10.0 l solutionb)add 10.0 L H2O into 3.846 L of 15.6 M solutionc)add 3.846 L H2O into 6.154 L of 15.6 M solutiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer?
Question Description
Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 M nitric acid from it,a)dilute 3.846 L of 15.6 M to 10.0 l solutionb)add 10.0 L H2O into 3.846 L of 15.6 M solutionc)add 3.846 L H2O into 6.154 L of 15.6 M solutiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 M nitric acid from it,a)dilute 3.846 L of 15.6 M to 10.0 l solutionb)add 10.0 L H2O into 3.846 L of 15.6 M solutionc)add 3.846 L H2O into 6.154 L of 15.6 M solutiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Commercial concentrated nitric acid is 15.6 M. To prepare 10 L of 6.0 M nitric acid from it,a)dilute 3.846 L of 15.6 M to 10.0 l solutionb)add 10.0 L H2O into 3.846 L of 15.6 M solutionc)add 3.846 L H2O into 6.154 L of 15.6 M solutiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer?.
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