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Comprehension Type
This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)
 
Passage
A handbook gives the concentration of water in a 2.772 M aqueous solution of NaOH as 998.0 g L " 1.
Q.
Molality of solution is
  • a)
    2.772 molal
  • b)
    2.778 molal
  • c)
    3.012 molal
  • d)
    2.172 molal
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Comprehension TypeThis section contains a passage describing theory, e...
Molarity = 2.772 M =2.772 mol L-1  Thus, NaOH =2.772 mol
 
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Comprehension TypeThis section contains a passage describing theory, e...
Explanation:
The molality of a solution is defined as the number of moles of solute per kilogram of solvent. In this case, the solute is NaOH and the solvent is water.

The given concentration of water in the solution is 998.0 g/L. This means that there are 998.0 grams of water in 1 liter of the solution.

To calculate the molality, we need to find the number of moles of NaOH in the solution. The molar mass of NaOH is 22.99 + 16.00 + 1.01 = 40.00 g/mol.

Step 1: Calculate the number of moles of NaOH
To find the number of moles of NaOH, we can use the formula:
moles = mass / molar mass

The mass of NaOH can be calculated using the formula:
mass = concentration * volume

In this case, the concentration of NaOH is 2.772 M and the volume is 1 liter.
mass = 2.772 mol/L * 1 L = 2.772 mol

Step 2: Calculate the molality
The molality can be calculated using the formula:
molality = moles of solute / mass of solvent (in kg)

In this case, the moles of solute (NaOH) is 2.772 mol and the mass of solvent (water) is 998.0 g. To convert the mass to kg, we divide by 1000.
mass of solvent = 998.0 g / 1000 = 0.998 kg

molality = 2.772 mol / 0.998 kg = 2.778 molal

Therefore, the molality of the solution is 2.778 molal.

Answer: The correct answer is option (b) 2.778 molal.
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Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)PassageA handbook gives the concentration of water in a 2.772 M aqueous solution of NaOH as 998.0 g L " 1.Q.Molality of solution isa)2.772 molalb)2.778 molalc)3.012 molald)2.172 molalCorrect answer is option 'B'. Can you explain this answer?
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Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)PassageA handbook gives the concentration of water in a 2.772 M aqueous solution of NaOH as 998.0 g L " 1.Q.Molality of solution isa)2.772 molalb)2.778 molalc)3.012 molald)2.172 molalCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)PassageA handbook gives the concentration of water in a 2.772 M aqueous solution of NaOH as 998.0 g L " 1.Q.Molality of solution isa)2.772 molalb)2.778 molalc)3.012 molald)2.172 molalCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)PassageA handbook gives the concentration of water in a 2.772 M aqueous solution of NaOH as 998.0 g L " 1.Q.Molality of solution isa)2.772 molalb)2.778 molalc)3.012 molald)2.172 molalCorrect answer is option 'B'. Can you explain this answer?.
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