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Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer?.

Solutions for Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

Here you can find the meaning of Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Δ = displacement caused when force is increased by a small amountP = external force appliedN = internal force in the member force appliedL = length of memberA = cross-sectional area of memberE = Modulus of elasticitySame symbol is used for partial and total differentiation and they are pretty obvious.What will be the work done during additional application of dp1?a)p1 dΔ1 + p2 dΔ2 + dp1d Δ1b)p1 dΔ1 + p2 dΔ2 +1⁄2dp1d Δ1c)p1 dΔ1 +1⁄2p2 dΔ2 + dp1d Δ1d)1⁄2p1 dΔ1 + p2 dΔ2 + dp1d Δ1Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.