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The present ages of three persons are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
  • a)
    8, 20, 28
  • b)
    16, 28, 36
  • c)
    20, 35, 45
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The present ages of three persons are in proportions 4 : 7 : 9. Eight ...
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
⇒ 20x = 80
⇒ x = 4
∴ Their present ages are 4x = 16 years,
7x = 28 years and 9x = 36 years respectively.
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Most Upvoted Answer
The present ages of three persons are in proportions 4 : 7 : 9. Eight ...
Let's assume the present ages of the three persons are 4x, 7x, and 9x respectively, where x is a common factor.

Eight years ago, their ages would have been (4x - 8), (7x - 8), and (9x - 8) respectively.

According to the given information, the sum of their ages eight years ago was 56.

So, (4x - 8) + (7x - 8) + (9x - 8) = 56

Combining like terms, we get:
20x - 24 = 56

Adding 24 to both sides, we get:
20x = 80

Dividing both sides by 20, we get:
x = 4

Now, we can find the present ages of the three persons:

Person 1: 4x = 4 * 4 = 16 years
Person 2: 7x = 7 * 4 = 28 years
Person 3: 9x = 9 * 4 = 36 years

Therefore, the present ages of the three persons are 16, 28, and 36 years respectively, which matches with option B: 16, 28, 36.
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The present ages of three persons are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).a)8, 20, 28b)16, 28, 36c)20, 35, 45d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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