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The enthalpies of formation of n2o and no at 298 Kelvin and 82 and 90 kilo joule per mole the enthalpy of the reaction n2o gas half O2 gives to 2no?
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The enthalpies of formation of n2o and no at 298 Kelvin and 82 and 90 ...
Enthalpy of the reaction N2O + 1/2 O2 → 2NO
The enthalpy change of a reaction can be determined by subtracting the sum of the enthalpies of formation of the reactants from the sum of the enthalpies of formation of the products.

Given Data:
- Enthalpy of formation of N2O = 82 kJ/mol
- Enthalpy of formation of NO = 90 kJ/mol

Calculating Enthalpy of Reaction:
- Enthalpy of reaction = [2(Enthalpy of formation of NO) - (Enthalpy of formation of N2O + 1/2 Enthalpy of formation of O2)]
- Enthalpy of reaction = [2(90 kJ/mol) - (82 kJ/mol + 1/2(0 kJ/mol))]
- Enthalpy of reaction = [180 kJ/mol - 82 kJ/mol]
- Enthalpy of reaction = 98 kJ/mol
Therefore, the enthalpy change for the reaction N2O + 1/2 O2 → 2NO is 98 kJ/mol. This means that the reaction is exothermic as it releases 98 kJ of energy per mole of reaction.
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The enthalpies of formation of n2o and no at 298 Kelvin and 82 and 90 kilo joule per mole the enthalpy of the reaction n2o gas half O2 gives to 2no?
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