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Predict the specific rotation of mixture of 30%(-)-2-bromobutane and 70%(+) enantiomer. [α]D of pure enantiomer is (-) -23.130. (Round off to two decimal places).Correct answer is between '9.20,9.30'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Predict the specific rotation of mixture of 30%(-)-2-bromobutane and 70%(+) enantiomer. [α]D of pure enantiomer is (-) -23.130. (Round off to two decimal places).Correct answer is between '9.20,9.30'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Predict the specific rotation of mixture of 30%(-)-2-bromobutane and 70%(+) enantiomer. [α]D of pure enantiomer is (-) -23.130. (Round off to two decimal places).Correct answer is between '9.20,9.30'. Can you explain this answer?.

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