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PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer?.

Solutions for PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice PASSAGE-5P and Q are isomers of dicarboxylic acid C4H4O4. Both decolorize Br2/H2O. On heating, P forms the cyclic anhydride. Upon treatment with dilute alkaline KMnO4, P as well as Q could produce one or more than one from S, T and U.a)Optically active S an d optically active pair (T, U)b)Optically in active S and optically in active pair (T, U)c)Optically active pair (T, U) and optically active Sd)Optically inactive pair (T, U)) and optically inactive SCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.