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Geometry and point group regarding [ZrMe6]2-
  • a)
    Octahedral and Oh
  • b)
    Distorted trigonal prismatic and C3v
  • c)
    Regular trigonal prismatic and D3h
  • d)
    Hexagonal and D6h
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Geometry andpoint group regarding [ZrMe6]2-a)Octahedral and Ohb)Distor...
 perfect trigonal prismatic geometry

perfect trigonal prismatic geometry has D3h point group.
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Geometry andpoint group regarding [ZrMe6]2-a)Octahedral and Ohb)Distor...
Octahedral and Oh
- The octahedral geometry is characterized by six ligands surrounding a central atom, forming a regular octahedron.
- The point group for octahedral geometry is Oh, which represents the symmetry elements present in the molecule.
- The symmetry elements in Oh point group include identity (E), six C3 rotations along the principal axis, four C2 rotations along the axes perpendicular to the principal axis, three σv planes containing the principal axis, and three σd planes perpendicular to the principal axis.
- The [ZrMe6]2- complex has an octahedral geometry because it has six ligands (Me) surrounding the central Zr atom.
- Therefore, the correct answer for the [ZrMe6]2- complex is option 'A' - Octahedral and Oh.

Distorted trigonal prismatic and C3v
- The distorted trigonal prismatic geometry is characterized by six ligands surrounding a central atom, forming a distorted prism-like shape.
- The point group for distorted trigonal prismatic geometry is C3v, which represents the symmetry elements present in the molecule.
- The symmetry elements in C3v point group include identity (E), three C3 rotations along the principal axis, three σv planes containing the principal axis, and one σh plane perpendicular to the principal axis.
- The [ZrMe6]2- complex does not have a distorted trigonal prismatic geometry because it does not have a prism-like shape.
- Therefore, the answer option 'B' - Distorted trigonal prismatic and C3v is incorrect.

Regular trigonal prismatic and D3h
- The regular trigonal prismatic geometry is characterized by six ligands surrounding a central atom, forming a regular prism-like shape.
- The point group for regular trigonal prismatic geometry is D3h, which represents the symmetry elements present in the molecule.
- The symmetry elements in D3h point group include identity (E), three C2 rotations along the principal axis, three C2 rotations along the axes perpendicular to the principal axis, six σd planes containing the principal axis, three σv planes containing the principal axis, and three σh planes perpendicular to the principal axis.
- The [ZrMe6]2- complex does not have a regular trigonal prismatic geometry because it has a distorted shape.
- Therefore, the answer option 'C' - Regular trigonal prismatic and D3h is incorrect.

Hexagonal and D6h
- The hexagonal geometry is characterized by six ligands surrounding a central atom, forming a hexagonal planar shape.
- The point group for hexagonal geometry is D6h, which represents the symmetry elements present in the molecule.
- The symmetry elements in D6h point group include identity (E), six C2 rotations along the principal axis, six C2 rotations along the axes perpendicular to the principal axis, six C2 rotations along the axes bisecting the angle between the principal axis and the axes perpendicular to it, six σd planes containing the principal axis, six σv planes containing the principal axis, and six σh planes perpendicular to the principal axis.
- The [ZrMe6]2- complex does not have a hexagonal geometry because it has a distorted shape.
- Therefore, the answer option '
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Geometry andpoint group regarding [ZrMe6]2-a)Octahedral and Ohb)Distorted trigonal prismatic and C3vc)Regular trigonal prismatic and D3hd)Hexagonal and D6hCorrect answer is option 'C'. Can you explain this answer?
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