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Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25) 
[AIEEE 2004]
  • a)
    Ti3+, V2+, Cr3+, Mn4+
  • b)
    Ti+, V4+, Cr6+, Mn7+
  • c)
    Ti4+, V3+, Cr2+, Mn3+
  • d)
    Ti2+, V3+, Cr4+, Mn5+
Correct answer is option 'D'. Can you explain this answer?
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Among the following series of transition metal ions, the one where all...
Ti2+,V3+,Cr4+ and Mn5+ show 1s22s22p63s23p64s03d2 electronic configuration.
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Among the following series of transition metal ions, the one where all...
Explanation:

In order to determine which series of transition metal ions have a 3d2 electronic configuration, we need to analyze the electron configurations of each ion.

The electron configuration of an atom or ion is a representation of how the electrons are distributed among the atomic orbitals. The 3d orbitals are a set of five orbitals that can hold a maximum of 10 electrons. The 3d2 electronic configuration means that there are 2 electrons occupying the 3d orbitals.

Let's analyze each option:

a) Ti3, V2, Cr3, Mn4
- Ti3: The atomic number of Ti is 22. In the ground state, the electron configuration of Ti is [Ar] 4s2 3d2. When Ti loses 3 electrons, it becomes Ti3+ with the electron configuration [Ar] 3d2. This matches the 3d2 electronic configuration.
- V2: The atomic number of V is 23. In the ground state, the electron configuration of V is [Ar] 4s2 3d3. When V loses 2 electrons, it becomes V2+ with the electron configuration [Ar] 3d3. This does not match the 3d2 electronic configuration.
- Cr3: The atomic number of Cr is 24. In the ground state, the electron configuration of Cr is [Ar] 4s2 3d4. When Cr loses 3 electrons, it becomes Cr3+ with the electron configuration [Ar] 3d3. This does not match the 3d2 electronic configuration.
- Mn4: The atomic number of Mn is 25. In the ground state, the electron configuration of Mn is [Ar] 4s2 3d5. When Mn loses 4 electrons, it becomes Mn4+ with the electron configuration [Ar] 3d1. This does not match the 3d2 electronic configuration.

b) Ti, V4, Cr6, Mn7
- Ti: The atomic number of Ti is 22. In the ground state, the electron configuration of Ti is [Ar] 4s2 3d2. This matches the 3d2 electronic configuration.
- V4: The atomic number of V is 23. In the ground state, the electron configuration of V is [Ar] 4s2 3d3. When V loses 4 electrons, it becomes V4+ with the electron configuration [Ar] 3d1. This does not match the 3d2 electronic configuration.
- Cr6: The atomic number of Cr is 24. In the ground state, the electron configuration of Cr is [Ar] 4s2 3d4. When Cr loses 6 electrons, it becomes Cr6+ with the electron configuration [Ar] 3d0. This does not match the 3d2 electronic configuration.
- Mn7: The atomic number of Mn is 25. In the ground state, the electron configuration of Mn is [Ar] 4s2 3d5. When Mn loses 7 electrons, it becomes Mn7+ with the electron configuration [Ar] 3d0. This does not match the 3d2 electronic configuration.

c) Ti4, V3, Cr2, Mn3
- Ti
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Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25)[AIEEE 2004]a)Ti3+, V2+, Cr3+, Mn4+b)Ti+, V4+, Cr6+, Mn7+c)Ti4+, V3+, Cr2+, Mn3+d)Ti2+, V3+, Cr4+, Mn5+Correct answer is option 'D'. Can you explain this answer?
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Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25)[AIEEE 2004]a)Ti3+, V2+, Cr3+, Mn4+b)Ti+, V4+, Cr6+, Mn7+c)Ti4+, V3+, Cr2+, Mn3+d)Ti2+, V3+, Cr4+, Mn5+Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25)[AIEEE 2004]a)Ti3+, V2+, Cr3+, Mn4+b)Ti+, V4+, Cr6+, Mn7+c)Ti4+, V3+, Cr2+, Mn3+d)Ti2+, V3+, Cr4+, Mn5+Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25)[AIEEE 2004]a)Ti3+, V2+, Cr3+, Mn4+b)Ti+, V4+, Cr6+, Mn7+c)Ti4+, V3+, Cr2+, Mn3+d)Ti2+, V3+, Cr4+, Mn5+Correct answer is option 'D'. Can you explain this answer?.
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