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Which of the following compounds will give a yellow precipitate with iodine and alkali?
- a)2-Hydroxypropane
- b)acetophenone
- c)methyl acetate
- d)acetamide
Correct answer is option 'A,B'. Can you explain this answer?
Verified Answer
Which of the following compounds will give a yellow precipitate with i...
TIPS/Formulae :
Iodoform reaction is given by the compounds containing
CH3CHO and CH3CH2OH.2-Hydroxypropane (CH3CHOHCH3) contains the grouping CH3CHOH— and acetophenone (C6H5COCH3) contains the grouping CH3CO– linked to carbon and hence give yellow ppt. with I2 and alkali—iodoform test.
In methyl acetate (CH3COOC2H5) and acetamide (CH3CO–NH2), CH3CO is attached to a hetero atom but not to carbon atom and hence both these compounds do not give iodoform test.
Iodoform reaction is given by the compounds containing
CH3CHO and CH3CH2OH.2-Hydroxypropane (CH3CHOHCH3) contains the grouping CH3CHOH— and acetophenone (C6H5COCH3) contains the grouping CH3CO– linked to carbon and hence give yellow ppt. with I2 and alkali—iodoform test.In methyl acetate (CH3COOC2H5) and acetamide (CH3CO–NH2), CH3CO is attached to a hetero atom but not to carbon atom and hence both these compounds do not give iodoform test.
Most Upvoted Answer
Which of the following compounds will give a yellow precipitate with i...
Answer:
Introduction:
In this question, we are asked to determine which of the given compounds will give a yellow precipitate with iodine and alkali. The reaction of iodine with alkali forms a complex, which is typically yellow in color. Let's analyze each compound and determine if it will give a yellow precipitate.
Analysis:
a) 2-Hydroxypropane:
2-Hydroxypropane is an alcohol, which contains a hydroxyl group (-OH). When this compound reacts with iodine and alkali, the hydroxyl group can oxidize to form a carbonyl compound. The carbonyl compound can further react with iodine to form a yellow precipitate. Therefore, 2-Hydroxypropane is expected to give a yellow precipitate.
b) Acetophenone:
Acetophenone is a ketone, which contains a carbonyl group (>C=O). Ketones do not react with iodine and alkali to form a yellow precipitate. Therefore, Acetophenone is not expected to give a yellow precipitate.
c) Methyl acetate:
Methyl acetate is an ester, which contains an ester functional group (-COO-). Esters do not react with iodine and alkali to form a yellow precipitate. Therefore, Methyl acetate is not expected to give a yellow precipitate.
d) Acetamide:
Acetamide is an amide, which contains an amide functional group (-CONH2). Amides do not react with iodine and alkali to form a yellow precipitate. Therefore, Acetamide is not expected to give a yellow precipitate.
Conclusion:
Based on the analysis, the compounds that are expected to give a yellow precipitate with iodine and alkali are 2-Hydroxypropane and Acetophenone. Therefore, the correct answer is option A and B.
Introduction:
In this question, we are asked to determine which of the given compounds will give a yellow precipitate with iodine and alkali. The reaction of iodine with alkali forms a complex, which is typically yellow in color. Let's analyze each compound and determine if it will give a yellow precipitate.
Analysis:
a) 2-Hydroxypropane:
2-Hydroxypropane is an alcohol, which contains a hydroxyl group (-OH). When this compound reacts with iodine and alkali, the hydroxyl group can oxidize to form a carbonyl compound. The carbonyl compound can further react with iodine to form a yellow precipitate. Therefore, 2-Hydroxypropane is expected to give a yellow precipitate.
b) Acetophenone:
Acetophenone is a ketone, which contains a carbonyl group (>C=O). Ketones do not react with iodine and alkali to form a yellow precipitate. Therefore, Acetophenone is not expected to give a yellow precipitate.
c) Methyl acetate:
Methyl acetate is an ester, which contains an ester functional group (-COO-). Esters do not react with iodine and alkali to form a yellow precipitate. Therefore, Methyl acetate is not expected to give a yellow precipitate.
d) Acetamide:
Acetamide is an amide, which contains an amide functional group (-CONH2). Amides do not react with iodine and alkali to form a yellow precipitate. Therefore, Acetamide is not expected to give a yellow precipitate.
Conclusion:
Based on the analysis, the compounds that are expected to give a yellow precipitate with iodine and alkali are 2-Hydroxypropane and Acetophenone. Therefore, the correct answer is option A and B.
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Which of the following compounds will give a yellow precipitate with iodine and alkali?a)2-Hydroxypropaneb)acetophenonec)methyl acetated)acetamideCorrect answer is option 'A,B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following compounds will give a yellow precipitate with iodine and alkali?a)2-Hydroxypropaneb)acetophenonec)methyl acetated)acetamideCorrect answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following compounds will give a yellow precipitate with iodine and alkali?a)2-Hydroxypropaneb)acetophenonec)methyl acetated)acetamideCorrect answer is option 'A,B'. Can you explain this answer?.
Which of the following compounds will give a yellow precipitate with iodine and alkali?a)2-Hydroxypropaneb)acetophenonec)methyl acetated)acetamideCorrect answer is option 'A,B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following compounds will give a yellow precipitate with iodine and alkali?a)2-Hydroxypropaneb)acetophenonec)methyl acetated)acetamideCorrect answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following compounds will give a yellow precipitate with iodine and alkali?a)2-Hydroxypropaneb)acetophenonec)methyl acetated)acetamideCorrect answer is option 'A,B'. Can you explain this answer?.
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