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Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:
- a)4 x 10-8M2
- b)1 x 10-8M2
- c)2 x 10-4M2
- d)1 x 10-4M2
Correct answer is option 'B'. Can you explain this answer?
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Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1...
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Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1...
Given data:
Equivalent conductance of saturated BaSO4 = 400 ohm-1cm2 equivalent-1
Specific conductance = 8 x 10-5 ohm-1cm-1
To calculate:
Ksp of BaSO4
Solution:
The equivalent conductance of a salt is defined as the conductance of a solution containing one gram equivalent of the salt dissolved in one litre of solution.
The specific conductance of a solution is defined as the conductance of a solution containing one gram of the salt dissolved in one litre of solution.
The relationship between equivalent conductance (Λ) and specific conductance (κ) is given by the equation:
Λ = κ × 1000/c
Where c is the concentration of the solution in moles per litre.
For a saturated solution of BaSO4, the concentration of Ba2+ and SO42- ions is equal to the solubility product (Ksp) of BaSO4.
The ionic equation of the dissolution of BaSO4 is:
BaSO4(s) ⇌ Ba2+(aq) + SO42-(aq)
The equivalent conductance of the saturated solution of BaSO4 is given as 400 ohm-1cm2 equivalent-1. Therefore, the specific conductance of the solution is calculated as:
κ = Λ × c/1000 = 400 × 1/1000 = 0.4 ohm-1cm-1
The specific conductance of the solution can also be calculated as:
κ = λ+/V+ + λ-/V-
Where λ+ and λ- are the equivalent conductances of Ba2+ and SO42- ions respectively, and V+ and V- are their respective molar conductivities.
The molar conductivity of an ion is defined as the conductance of a solution containing one mole of the ion dissolved in one litre of solution.
For Ba2+ and SO42- ions, the molar conductivities are given as:
λ+ = 132.3 ohm-1cm2mol-1 and λ- = 160.0 ohm-1cm2mol-1 respectively.
Substituting these values in the equation, we get:
0.4 = λ+/V+ + λ-/V-
For a saturated solution of BaSO4, the concentration of Ba2+ and SO42- ions is equal to the solubility product (Ksp) of BaSO4.
The molar conductivity of a saturated solution of BaSO4 is given as:
λm = λ+(Ba2+) + λ-(SO42-) = 132.3 + 160.0 = 292.3 ohm-1cm2mol-1
The molar conductivity of a saturated solution of BaSO4 can also be calculated as:
λm = κ × 1000/2c = 400 × 1000/2 × 1/1000 = 200 ohm-1cm2mol-1
Substituting these values in the equation, we get:
0.4 = λm/Vm
Where Vm is the molar volume of the solution.
The molar volume of the solution is given as:
Vm = 1000/c = 1000/2 × 1/1000 = 0.5 cm3mol-1
Substituting these values in the equation, we
Equivalent conductance of saturated BaSO4 = 400 ohm-1cm2 equivalent-1
Specific conductance = 8 x 10-5 ohm-1cm-1
To calculate:
Ksp of BaSO4
Solution:
The equivalent conductance of a salt is defined as the conductance of a solution containing one gram equivalent of the salt dissolved in one litre of solution.
The specific conductance of a solution is defined as the conductance of a solution containing one gram of the salt dissolved in one litre of solution.
The relationship between equivalent conductance (Λ) and specific conductance (κ) is given by the equation:
Λ = κ × 1000/c
Where c is the concentration of the solution in moles per litre.
For a saturated solution of BaSO4, the concentration of Ba2+ and SO42- ions is equal to the solubility product (Ksp) of BaSO4.
The ionic equation of the dissolution of BaSO4 is:
BaSO4(s) ⇌ Ba2+(aq) + SO42-(aq)
The equivalent conductance of the saturated solution of BaSO4 is given as 400 ohm-1cm2 equivalent-1. Therefore, the specific conductance of the solution is calculated as:
κ = Λ × c/1000 = 400 × 1/1000 = 0.4 ohm-1cm-1
The specific conductance of the solution can also be calculated as:
κ = λ+/V+ + λ-/V-
Where λ+ and λ- are the equivalent conductances of Ba2+ and SO42- ions respectively, and V+ and V- are their respective molar conductivities.
The molar conductivity of an ion is defined as the conductance of a solution containing one mole of the ion dissolved in one litre of solution.
For Ba2+ and SO42- ions, the molar conductivities are given as:
λ+ = 132.3 ohm-1cm2mol-1 and λ- = 160.0 ohm-1cm2mol-1 respectively.
Substituting these values in the equation, we get:
0.4 = λ+/V+ + λ-/V-
For a saturated solution of BaSO4, the concentration of Ba2+ and SO42- ions is equal to the solubility product (Ksp) of BaSO4.
The molar conductivity of a saturated solution of BaSO4 is given as:
λm = λ+(Ba2+) + λ-(SO42-) = 132.3 + 160.0 = 292.3 ohm-1cm2mol-1
The molar conductivity of a saturated solution of BaSO4 can also be calculated as:
λm = κ × 1000/2c = 400 × 1000/2 × 1/1000 = 200 ohm-1cm2mol-1
Substituting these values in the equation, we get:
0.4 = λm/Vm
Where Vm is the molar volume of the solution.
The molar volume of the solution is given as:
Vm = 1000/c = 1000/2 × 1/1000 = 0.5 cm3mol-1
Substituting these values in the equation, we
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Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer?
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Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer?.
Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer?.
Solutions for Equivalent conductance of saturated BaSO4 is 400 ohm-1cm2 equivalemt-1 and specific conductance is 8 x 10-5 ohm-1cm-1. Hence, ksp of BaSO4 is:a)4 x 10-8M2b)1 x 10-8M2c)2 x 10-4M2d)1 x 10-4M2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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