Chemistry Exam > Chemistry Questions > A 0.05 N solution of a salt occupying a volum...
Start Learning for Free
A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:
Correct answer is between '30.00,31.00'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A 0.05 N solution of a salt occupying a volume between two platinum el...
Most Upvoted Answer
A 0.05 N solution of a salt occupying a volume between two platinum el...
Free Test
FREE
| Start Free Test |
Community Answer
A 0.05 N solution of a salt occupying a volume between two platinum el...
The resistance (R) of a solution can be calculated using the formula:
R = ρ * (L/A)
Where:
R = resistance
ρ = resistivity of the solution
L = distance between the electrodes
A = area of the electrodes
In this case, we are given the resistance (R = 250 ohm), the distance between the electrodes (L = 1.72 cm), and the area of the electrodes (A = 4.5 cm^2). We need to calculate the resistivity (ρ) of the solution.
The resistivity can be calculated using the formula:
ρ = R * (A/L)
ρ = 250 ohm * (4.5 cm^2 / 1.72 cm)
ρ = 655.813 ohm * cm
The equivalent conductance (Λ) of a solution can be calculated using the formula:
Λ = 1/R * (L/A)
Λ = 1/250 ohm * (1.72 cm / 4.5 cm^2)
Λ = 0.0028 S/cm
Therefore, the equivalent conductance of the solution is 0.0028 S/cm.
R = ρ * (L/A)
Where:
R = resistance
ρ = resistivity of the solution
L = distance between the electrodes
A = area of the electrodes
In this case, we are given the resistance (R = 250 ohm), the distance between the electrodes (L = 1.72 cm), and the area of the electrodes (A = 4.5 cm^2). We need to calculate the resistivity (ρ) of the solution.
The resistivity can be calculated using the formula:
ρ = R * (A/L)
ρ = 250 ohm * (4.5 cm^2 / 1.72 cm)
ρ = 655.813 ohm * cm
The equivalent conductance (Λ) of a solution can be calculated using the formula:
Λ = 1/R * (L/A)
Λ = 1/250 ohm * (1.72 cm / 4.5 cm^2)
Λ = 0.0028 S/cm
Therefore, the equivalent conductance of the solution is 0.0028 S/cm.
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?
Question Description
A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?.
A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?.
Solutions for A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?, a detailed solution for A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? has been provided alongside types of A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup