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A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:
Correct answer is between '30.00,31.00'. Can you explain this answer?
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The resistance (R) of a solution can be calculated using the formula:
R = ρ * (L/A)
Where:
R = resistance
ρ = resistivity of the solution
L = distance between the electrodes
A = area of the electrodes
In this case, we are given the resistance (R = 250 ohm), the distance between the electrodes (L = 1.72 cm), and the area of the electrodes (A = 4.5 cm^2). We need to calculate the resistivity (ρ) of the solution.
The resistivity can be calculated using the formula:
ρ = R * (A/L)
ρ = 250 ohm * (4.5 cm^2 / 1.72 cm)
ρ = 655.813 ohm * cm
The equivalent conductance (Λ) of a solution can be calculated using the formula:
Λ = 1/R * (L/A)
Λ = 1/250 ohm * (1.72 cm / 4.5 cm^2)
Λ = 0.0028 S/cm
Therefore, the equivalent conductance of the solution is 0.0028 S/cm.
R = ρ * (L/A)
Where:
R = resistance
ρ = resistivity of the solution
L = distance between the electrodes
A = area of the electrodes
In this case, we are given the resistance (R = 250 ohm), the distance between the electrodes (L = 1.72 cm), and the area of the electrodes (A = 4.5 cm^2). We need to calculate the resistivity (ρ) of the solution.
The resistivity can be calculated using the formula:
ρ = R * (A/L)
ρ = 250 ohm * (4.5 cm^2 / 1.72 cm)
ρ = 655.813 ohm * cm
The equivalent conductance (Λ) of a solution can be calculated using the formula:
Λ = 1/R * (L/A)
Λ = 1/250 ohm * (1.72 cm / 4.5 cm^2)
Λ = 0.0028 S/cm
Therefore, the equivalent conductance of the solution is 0.0028 S/cm.
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A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?
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A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?.
A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm2 has a resistance of 250 ohm. Calculate the equivalent conductance (in s–1 cm2 eq–1) of the solution [rounded up to two decimal places]:Correct answer is between '30.00,31.00'. Can you explain this answer?.
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