If 0.01 M solution of an electrolyte has a resistance of 40 ohm in a cell having a cell constant of 0.4 cm–1, then, its molar conductance in ohm–1 cm2 mol–1 will be:Correct answer is '1000'. Can you explain this answer?

Question

If 0.01 M solution of an electrolyte has a resistance of 40 ohm in a cell having a cell constant of 0.4 cm&ndash;1, then, its molar conductance in ohm&ndash;1 cm2 mol&ndash;1 will be:Correct answer is '1000'. Can you explain this answer?

Answer

The conductivity of the solution can be calculated using the formula:

conductivity (k) = 1 / (resistance x cell constant)

Substituting the given values:

k = 1 / (40 ohm x 0.4 cm)
k = 0.0625 S/cm

The concentration of the electrolyte can be calculated using the formula:

concentration (C) = k / (F x A)

where F is the Faraday constant (96485 C/mol) and A is the area of the electrodes in cm2.

Assuming a standard electrode area of 1 cm2:

C = 0.0625 S/cm / (96485 C/mol x 1 cm2)
C = 6.47 x 10^-7 mol/cm3 or 0.01 M (approx)

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