A system filled with 0.505 mol of gas contracts reversibly from 1L to ...
q = -1270J
Even through process is isothermal but overall ΔU change is not zero. So. applying first law
ΔU = q + w = -1270 + 2688 = 14187
View all questions of this test
A system filled with 0.505 mol of gas contracts reversibly from 1L to ...
In order to solve this problem, we can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure of the gas (constant in this case)
V = Volume of the gas
n = Number of moles of gas
R = Ideal gas constant
T = Temperature of the gas (constant in this case)
We are given:
n = 0.505 mol (number of moles of gas)
V1 = 1L (initial volume of the gas)
V2 = 0.10L (final volume of the gas)
Since the temperature is constant, we can rewrite the ideal gas law equation as:
P1V1 = P2V2
Where:
P1 = Initial pressure of the gas
P2 = Final pressure of the gas
We need to find P2, the final pressure of the gas.
Rearranging the equation, we get:
P2 = (P1V1) / V2
Substituting the given values, we have:
P2 = (P1 * 1L) / 0.10L
Since the pressure is constant, P1 = P2.
P1 = P2 = (P1 * 1L) / 0.10L
Multiplying both sides by 0.10L, we get:
0.10L * P1 = P1 * 1L
Canceling out P1 on both sides, we have:
0.10L = 1L
Dividing both sides by 1L, we get:
0.10 = 1
This is not a valid conclusion, as it implies that 0.10 is equal to 1, which is not true.
Therefore, there must be an error in the problem statement or the calculations.