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Graph of 1/v versus x of a particle, where v is speed in metre per second and x is position moving along a straight line is as shown in figure. the time taken by particle to move from x =0m to X = 10 metre is?
Most Upvoted Answer
Graph of 1/v versus x of a particle, where v is speed in metre per sec...
Explanation:

The graph shows the inverse of velocity versus distance, which means that the gradient of the graph is proportional to the time taken to travel a certain distance. Therefore, we need to find the gradient of the line and then take the reciprocal of it to get the time taken to travel from x=0m to x=10m.

Finding Gradient:
To find the gradient of the line, we need to choose two points on the graph and calculate the change in 1/v and x between them. One convenient set of points is (1, 1) and (5, 0.5) as they lie on the line and the values are easy to work with.

Change in 1/v = 0.5 - 1 = -0.5
Change in x = 5 - 1 = 4

Gradient = change in 1/v / change in x = -0.5 / 4 = -0.125

Finding Time Taken:
Now we need to take the reciprocal of the gradient to get the time taken to travel 1 metre. Then we can multiply it by 10 to get the time taken to travel 10 metres.

Time taken to travel 1 metre = 1 / gradient = 1 / -0.125 = -8 seconds
(Note: the negative sign indicates that the particle is moving in the negative direction)

Time taken to travel 10 metres = 10 x time taken to travel 1 metre = 10 x (-8) = -80 seconds

Answer:
The time taken by the particle to move from x=0m to x=10m is 80 seconds in the negative direction.
Community Answer
Graph of 1/v versus x of a particle, where v is speed in metre per sec...
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Graph of 1/v versus x of a particle, where v is speed in metre per second and x is position moving along a straight line is as shown in figure. the time taken by particle to move from x =0m to X = 10 metre is?
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