Class 12 Exam > Class 12 Questions > If a wire is stretched 20% more than its init...
Start Learning for Free
If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is?
Most Upvoted Answer
If a wire is stretched 20% more than its initial length. The percentag...
Calculation of Percentage Increase in Resistance of a Wire When Stretched 20% More Than Its Initial Length
Definition: Resistance is the opposition that a substance offers to the flow of electric current. When a wire is stretched, its resistance increases due to the increase in length and decrease in cross-sectional area.
Formula: The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. Therefore, the formula for resistance is R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
Calculation:
1. Let the initial length of the wire be L1 and the final length be L2, where L2 = L1 + 0.2L1 = 1.2L1 (20% more than L1).
2. Since the cross-sectional area of the wire remains constant, the formula for resistance becomes R2 = ρL2/A.
3. Substituting L2 = 1.2L1 in the above equation, we get R2 = ρ(1.2L1)/A.
4. Simplifying the equation, we get R2 = 1.2(ρL1/A) = 1.2R1, where R1 is the initial resistance of the wire.
5. Therefore, the percentage increase in resistance is given by (R2 - R1)/R1 x 100%.
6. Substituting the values of R1 and R2, we get (1.2R1 - R1)/R1 x 100% = 0.2 x 100% = 20%.
Conclusion: The percentage increase in resistance of a wire when stretched 20% more than its initial length is 20%. This is because the resistance is directly proportional to the length of the wire and increases when the length increases.
Definition: Resistance is the opposition that a substance offers to the flow of electric current. When a wire is stretched, its resistance increases due to the increase in length and decrease in cross-sectional area.
Formula: The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. Therefore, the formula for resistance is R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
Calculation:
1. Let the initial length of the wire be L1 and the final length be L2, where L2 = L1 + 0.2L1 = 1.2L1 (20% more than L1).
2. Since the cross-sectional area of the wire remains constant, the formula for resistance becomes R2 = ρL2/A.
3. Substituting L2 = 1.2L1 in the above equation, we get R2 = ρ(1.2L1)/A.
4. Simplifying the equation, we get R2 = 1.2(ρL1/A) = 1.2R1, where R1 is the initial resistance of the wire.
5. Therefore, the percentage increase in resistance is given by (R2 - R1)/R1 x 100%.
6. Substituting the values of R1 and R2, we get (1.2R1 - R1)/R1 x 100% = 0.2 x 100% = 20%.
Conclusion: The percentage increase in resistance of a wire when stretched 20% more than its initial length is 20%. This is because the resistance is directly proportional to the length of the wire and increases when the length increases.
Community Answer
If a wire is stretched 20% more than its initial length. The percentag...
44% increase.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is?
Question Description
If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is?.
If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is?.
Solutions for If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? defined & explained in the simplest way possible. Besides giving the explanation of
If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is?, a detailed solution for If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? has been provided alongside types of If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? theory, EduRev gives you an
ample number of questions to practice If a wire is stretched 20% more than its initial length. The percentage increase in resistence of wire is? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup