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If a copper wire is stretched to make it 0.1% longer. The percentage change in its resistance is: 
  • a)
    0.2 % increase
  • b)
    0.2 % decrease
  • c)
    0.1 % increase
  • d)
    0.1 % decrease
Correct answer is option 'A'. Can you explain this answer?
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Explanation:

The resistance of a conductor depends on its length, cross-sectional area, and resistivity. The resistance of a wire is given by the formula:

R = ρL/A

where R is resistance, ρ is resistivity, L is the length of the wire, and A is the cross-sectional area.

When a wire is stretched, its length increases and its cross-sectional area decreases. The resistivity of the wire remains constant.

Percentage change in length = 0.1%

Percentage change in cross-sectional area = -0.1% (since the area decreases)

Percentage change in resistance = percentage change in length + percentage change in cross-sectional area

= 0.1% - 0.1%

= 0.2% increase

Therefore, the percentage change in resistance is 0.2% increase.
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If a copper wire is stretched to make it 0.1% longer. The percentage change in its resistance is:a)0.2 % increaseb)0.2 % decreasec)0.1 % increased)0.1 % decreaseCorrect answer is option 'A'. Can you explain this answer?
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