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The degree of dissociation of Br2(g) into Br(g) if at 600K and a total pressure is 0.1 atm is ____(therefore, kP = 0.255atm). (Round off to two decimal places).
Correct answer is between '0.60,0.65'. Can you explain this answer?
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Calculation of Degree of Dissociation of Br2(g)
Given parameters:
- Temperature (T) = 600K
- Total pressure (P) = 0.1 atm
- kP = 0.255 atm
1. Write the balanced chemical equation for the dissociation of Br2(g) into Br(g).
Br2(g) ⇌ 2Br(g)
2. Write the expression for the equilibrium constant (Kp).
Kp = (PBr)^2 / PBr2
where PBr and PBr2 are the partial pressures of Br and Br2, respectively.
3. Write the expression for the degree of dissociation (α) of Br2.
α = (2PBr / PBr2)
4. Substitute the given values into the expression for Kp.
0.255 = (PBr)^2 / PBr2
5. Solve for PBr.
PBr = √(0.255PBr2)
6. Substitute the expression for PBr into the expression for α.
α = (2√(0.255PBr2) / PBr2)
7. Simplify the expression for α.
α = 2√(0.255 / PBr2)
8. Substitute the value of PBr2 (which is equal to P - PBr) into the expression for α.
α = 2√(0.255 / (P - √(0.255PBr2)))
9. Substitute the given value of P into the expression for α.
α = 2√(0.255 / (0.1 - √(0.255PBr2)))
10. Use the iterative method to solve for α.
Starting with an assumed value of α, substitute it into the expression for PBr2 and then into the expression for α until the value of α converges.
After several iterations, the value of α is found to be between 0.60 and 0.65. Therefore, the degree of dissociation of Br2(g) into Br(g) at 600K and a total pressure of 0.1 atm is approximately 0.63 (rounded off to two decimal places).
Given parameters:
- Temperature (T) = 600K
- Total pressure (P) = 0.1 atm
- kP = 0.255 atm
1. Write the balanced chemical equation for the dissociation of Br2(g) into Br(g).
Br2(g) ⇌ 2Br(g)
2. Write the expression for the equilibrium constant (Kp).
Kp = (PBr)^2 / PBr2
where PBr and PBr2 are the partial pressures of Br and Br2, respectively.
3. Write the expression for the degree of dissociation (α) of Br2.
α = (2PBr / PBr2)
4. Substitute the given values into the expression for Kp.
0.255 = (PBr)^2 / PBr2
5. Solve for PBr.
PBr = √(0.255PBr2)
6. Substitute the expression for PBr into the expression for α.
α = (2√(0.255PBr2) / PBr2)
7. Simplify the expression for α.
α = 2√(0.255 / PBr2)
8. Substitute the value of PBr2 (which is equal to P - PBr) into the expression for α.
α = 2√(0.255 / (P - √(0.255PBr2)))
9. Substitute the given value of P into the expression for α.
α = 2√(0.255 / (0.1 - √(0.255PBr2)))
10. Use the iterative method to solve for α.
Starting with an assumed value of α, substitute it into the expression for PBr2 and then into the expression for α until the value of α converges.
After several iterations, the value of α is found to be between 0.60 and 0.65. Therefore, the degree of dissociation of Br2(g) into Br(g) at 600K and a total pressure of 0.1 atm is approximately 0.63 (rounded off to two decimal places).
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The degree of dissociation of Br2(g) into Br(g) if at 600K and a total pressure is 0.1 atm is ____(therefore, kP = 0.255atm). (Round off to two decimal places).Correct answer is between '0.60,0.65'. Can you explain this answer?
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The degree of dissociation of Br2(g) into Br(g) if at 600K and a total pressure is 0.1 atm is ____(therefore, kP = 0.255atm). (Round off to two decimal places).Correct answer is between '0.60,0.65'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The degree of dissociation of Br2(g) into Br(g) if at 600K and a total pressure is 0.1 atm is ____(therefore, kP = 0.255atm). (Round off to two decimal places).Correct answer is between '0.60,0.65'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The degree of dissociation of Br2(g) into Br(g) if at 600K and a total pressure is 0.1 atm is ____(therefore, kP = 0.255atm). (Round off to two decimal places).Correct answer is between '0.60,0.65'. Can you explain this answer?.
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