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The total number of hardware interrupts present in 8085 microprocessor are
  • a)
    8
  • b)
    5
  • c)
    16
  • d)
    13
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The total number of hardware interrupts present in 8085 microprocessor...
8085 microprocessor contains,
When microprocessors receive interrupt signals through pins (hardware) of the microprocessor, they are known as Hardware Interrupts
Five hardware interrupts: TRAP, RST 5.5, RST 6.5, RST 7.5 and INTR
Software Interrupts are those which are inserted in between the program, these are mnemonics of the microprocessor.
Eight software interrupts: RST 0 to RST 7
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Most Upvoted Answer
The total number of hardware interrupts present in 8085 microprocessor...
The correct answer is option 'B' - 5.

Explanation:
The 8085 microprocessor is a widely used 8-bit microprocessor architecture developed by Intel. It is a simple and basic microprocessor that was widely used in various applications.

The 8085 microprocessor supports a total of 5 hardware interrupts. These interrupts are used to handle various events and to provide a way for external devices to communicate with the microprocessor.

Here are the 5 hardware interrupts supported by the 8085 microprocessor:

1. INTR (Interrupt Request):
- The INTR input is used to request an interrupt.
- It is a non-maskable interrupt (NMI) that has the highest priority.
- It is generally used for critical events that require immediate attention.
- The microprocessor responds to the INTR signal by executing an interrupt service routine (ISR).

2. RST 7.5 (Restart 7.5):
- The RST 7.5 input is used to generate a maskable interrupt.
- It has the second-highest priority after the INTR interrupt.
- When the RST 7.5 signal is activated, the microprocessor jumps to memory location 003C (hexadecimal) to execute the ISR.

3. RST 6.5 (Restart 6.5):
- The RST 6.5 input is also used to generate a maskable interrupt.
- It has the third-highest priority among the interrupts.
- When the RST 6.5 signal is activated, the microprocessor jumps to memory location 0034 (hexadecimal) to execute the ISR.

4. RST 5.5 (Restart 5.5):
- The RST 5.5 input is used to generate a maskable interrupt.
- It has the fourth-highest priority among the interrupts.
- When the RST 5.5 signal is activated, the microprocessor jumps to memory location 002C (hexadecimal) to execute the ISR.

5. TRAP:
- The TRAP input is used to generate a non-maskable interrupt.
- It has the lowest priority among the interrupts.
- It is generally used for critical events that require immediate attention, similar to the INTR interrupt.
- When the TRAP signal is activated, the microprocessor jumps to memory location 0024 (hexadecimal) to execute the ISR.

These 5 hardware interrupts provide a way for the microprocessor to handle various events and communicate with external devices. By using these interrupts, the microprocessor can respond to critical events in real-time and perform the necessary actions accordingly.
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The total number of hardware interrupts present in 8085 microprocessor area)8b)5c)16d)13Correct answer is option 'B'. Can you explain this answer?
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