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A gas expand isothermally against a constant external pressure of 1 atm from a volume of 10 dm3 to a volume of 20 dm3. In this process, it absorbs 800J of thermal energy from its surroundings. The ΔU for this process?
  • a)
    -231J
  • b)
    -190J
  • c)
    zero
  • d)
    infinity
Correct answer is option 'A'. Can you explain this answer?
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A gas expand isothermally against a constant external pressure of 1 at...
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A gas expand isothermally against a constant external pressure of 1 at...
Work done by the gas is given by the equation:

work done = external pressure x change in volume

Given that the external pressure is constant at 1 atm and the change in volume is from 10 dm3 to 20 dm3, we can calculate the work done as follows:

work done = 1 atm x (20 dm3 - 10 dm3)
work done = 1 atm x 10 dm3
work done = 10 atm dm3

Since 1 atm dm3 is equivalent to 101.3 J, we can convert the work done to joules:

work done = 10 atm dm3 x 101.3 J/atm dm3
work done = 1013 J

Therefore, the work done by the gas in the isothermal expansion is 1013 J.
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A gas expand isothermally against a constant external pressure of 1 at...
I think option c is correct because of isothermal process
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A gas expand isothermally against a constant external pressure of 1 atm from a volume of 10 dm3 to a volume of 20 dm3. In this process, it absorbs 800J of thermal energy from its surroundings. TheΔU for this process?a)-231Jb)-190Jc)zerod)infinityCorrect answer is option 'A'. Can you explain this answer?
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