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For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel is
- a)0.25 m/s
- b)1.2 m/s
- c)2.0 m/s
- d)3.5 m/s
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For a uniform flow depth of 2 m in a rectangular open channel having a...
Velocity in an open channel is given by
where
n = Manning’s Coefficient
R = Hydraulic radius = (Wetted Area/ Wetted Perimeter)
S = Bed Slope
Most Upvoted Answer
For a uniform flow depth of 2 m in a rectangular open channel having a...
Understanding Flow in Open Channels
To determine the velocity of flow in a rectangular open channel, we can use Manning's equation, which is given by:
V = (1/n) * R^(2/3) * S^(1/2)
where:
- V = velocity (m/s)
- n = Manning’s coefficient (0.02 in this case)
- R = hydraulic radius (m)
- S = slope of the channel bed (0.0016)
Calculating the Hydraulic Radius
The hydraulic radius (R) for a rectangular channel is calculated as:
R = A / P
where:
- A = cross-sectional area (m²)
- P = wetted perimeter (m)
For a rectangular open channel with a width (b) of 4 m and a depth (h) of 2 m:
- Cross-sectional area (A) = b * h = 4 m * 2 m = 8 m²
- Wetted perimeter (P) = b + 2h = 4 m + 2 * 2 m = 8 m
Thus, the hydraulic radius is:
R = A / P = 8 m² / 8 m = 1 m
Applying Manning's Equation
Now substituting the values into Manning's equation:
V = (1/0.02) * (1)^(2/3) * (0.0016)^(1/2)
Calculating further:
- V = 50 * 1 * 0.04 (approximate value of sqrt(0.0016))
- V = 50 * 0.04 = 2.0 m/s
Conclusion
The calculated velocity of the channel flow is 2.0 m/s, confirming that the correct answer is option 'C'.
To determine the velocity of flow in a rectangular open channel, we can use Manning's equation, which is given by:
V = (1/n) * R^(2/3) * S^(1/2)
where:
- V = velocity (m/s)
- n = Manning’s coefficient (0.02 in this case)
- R = hydraulic radius (m)
- S = slope of the channel bed (0.0016)
Calculating the Hydraulic Radius
The hydraulic radius (R) for a rectangular channel is calculated as:
R = A / P
where:
- A = cross-sectional area (m²)
- P = wetted perimeter (m)
For a rectangular open channel with a width (b) of 4 m and a depth (h) of 2 m:
- Cross-sectional area (A) = b * h = 4 m * 2 m = 8 m²
- Wetted perimeter (P) = b + 2h = 4 m + 2 * 2 m = 8 m
Thus, the hydraulic radius is:
R = A / P = 8 m² / 8 m = 1 m
Applying Manning's Equation
Now substituting the values into Manning's equation:
V = (1/0.02) * (1)^(2/3) * (0.0016)^(1/2)
Calculating further:
- V = 50 * 1 * 0.04 (approximate value of sqrt(0.0016))
- V = 50 * 0.04 = 2.0 m/s
Conclusion
The calculated velocity of the channel flow is 2.0 m/s, confirming that the correct answer is option 'C'.
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For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer?
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For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer? for Railways 2025 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Railways 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer?.
For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer? for Railways 2025 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Railways 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer?.
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For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of For a uniform flow depth of 2 m in a rectangular open channel having a width of 4 m and a bed slope of 0.0016, Manning’s coefficient is found to be 0.02. The velocity of the channel isa)0.25 m/sb)1.2 m/sc)2.0 m/sd)3.5 m/sCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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