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An object of weight 49 N is accelerated across a level surface at 0.20 m/s2. The net force acting on the object is (g = 9.8 m/s2)
  • a)
    9.8 N
  • b)
    1.0 N
  • c)
    5.0 N
  • d)
    0.5 N
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An object of weight 49 N is accelerated across a level surface at 0.20...
W = mg
49 = m × 9.8
m = 5 kg
Net Force = ma = 5 × 0.2 = 1.0 N
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Most Upvoted Answer
An object of weight 49 N is accelerated across a level surface at 0.20...
Explanation:

To find the net force acting on the object, we need to use Newton's second law of motion, which states that the net force on an object is equal to the product of its mass and acceleration.

Given:
Weight of the object = 49 N
Acceleration = 0.20 m/s^2

Step 1: Convert weight to mass
Weight is the force exerted on an object due to gravity, and it is equal to the mass of the object multiplied by the acceleration due to gravity (g = 9.8 m/s^2).

Weight = mass x acceleration due to gravity

49 N = mass x 9.8 m/s^2

mass = 49 N / 9.8 m/s^2

mass = 5 kg

Step 2: Calculate the net force
Now that we have the mass and acceleration, we can calculate the net force using Newton's second law of motion.

Net force = mass x acceleration

Net force = 5 kg x 0.20 m/s^2

Net force = 1 N

Therefore, the net force acting on the object is 1 N.

Conclusion:
The correct answer is option B) 1.0 N.
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An object of weight 49 N is accelerated across a level surface at 0.20 m/s2. The net force acting on the object is (g = 9.8 m/s2)a)9.8 Nb)1.0 Nc)5.0 Nd)0.5 NCorrect answer is option 'B'. Can you explain this answer?
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