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The magnetic field intensity in a material whose relative permeability is 1 when the flux density is 0.005 T is:
- a)250 AT/m
- b)452 AT/m
- c)1775 AT/m
- d)3980 AT/m
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The magnetic field intensity in a material whose relative permeability...
The relation between magnetic field intensity (H) and magnetic flux density (B) is
B = μ H
Most Upvoted Answer
The magnetic field intensity in a material whose relative permeability...
Given:
Relative permeability (μr) = 1
Flux density (B) = 0.005 T
To find:
Magnetic field intensity (H)
Solution:
The relationship between magnetic field intensity (H) and flux density (B) is given by the equation:
B = μ0 * μr * H
Where:
μ0 = Permeability of free space = 4π × 10^−7 T·m/A
Step 1:
Substitute the given values into the equation to find the magnetic field intensity (H):
0.005 T = (4π × 10^−7 T·m/A) * 1 * H
Simplify the equation:
H = 0.005 T / (4π × 10^−7 T·m/A)
Step 2:
Evaluate the expression:
H = (0.005 T) / (4π × 10^−7 T·m/A)
H = (0.005) / (4π × 10^−7) m/A
H = (0.005) / (4 × 3.1416 × 10^−7) m/A
H = (0.005) / (12.5664 × 10^−7) m/A
H = (0.005) / (1.25664 × 10^−5) m/A
H = (0.005) / (0.0000125664) m/A
H ≈ 3980 A/m
Answer:
The magnetic field intensity in the material when the flux density is 0.005 T and the relative permeability is 1 is approximately 3980 A/m. Therefore, the correct answer is option (d) 3980 AT/m.
Relative permeability (μr) = 1
Flux density (B) = 0.005 T
To find:
Magnetic field intensity (H)
Solution:
The relationship between magnetic field intensity (H) and flux density (B) is given by the equation:
B = μ0 * μr * H
Where:
μ0 = Permeability of free space = 4π × 10^−7 T·m/A
Step 1:
Substitute the given values into the equation to find the magnetic field intensity (H):
0.005 T = (4π × 10^−7 T·m/A) * 1 * H
Simplify the equation:
H = 0.005 T / (4π × 10^−7 T·m/A)
Step 2:
Evaluate the expression:
H = (0.005 T) / (4π × 10^−7 T·m/A)
H = (0.005) / (4π × 10^−7) m/A
H = (0.005) / (4 × 3.1416 × 10^−7) m/A
H = (0.005) / (12.5664 × 10^−7) m/A
H = (0.005) / (1.25664 × 10^−5) m/A
H = (0.005) / (0.0000125664) m/A
H ≈ 3980 A/m
Answer:
The magnetic field intensity in the material when the flux density is 0.005 T and the relative permeability is 1 is approximately 3980 A/m. Therefore, the correct answer is option (d) 3980 AT/m.
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The magnetic field intensity in a material whose relative permeability is 1 when the flux density is 0.005 T is:a)250 AT/mb)452 AT/mc)1775 AT/md)3980 AT/mCorrect answer is option 'D'. Can you explain this answer?
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