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A particle is projected from horizontal making an angle 60° with initial velocity 40m/s. Find the time taken to the particle to make an angle 45° from horizontal.plz explain briefly plz....
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A particle is projected from horizontal making an angle 60° with initi...
Projectile Motion Analysis:

Given Data:
- Initial angle of projection: 60°
- Initial velocity: 40 m/s
- Angle to be achieved: 45°

Time Taken Calculation:
1. Resolve the initial velocity into horizontal and vertical components:
- Initial horizontal component: 40 * cos(60°)
- Initial vertical component: 40 * sin(60°)
2. To find the time taken to reach 45° from horizontal, we need to consider the vertical motion of the particle.
3. Use the vertical component of velocity to calculate the time taken to reach the highest point:
- Vertical component of velocity at highest point is 0 m/s.
- Use the equation v = u + at, where v = 0, u = initial vertical component, a = acceleration due to gravity (-9.8 m/s^2), t = time.
- Solve for t to find the time taken to reach the highest point.
4. The time taken to reach the highest point is the same as the time taken to reach 45° from horizontal, as the projectile motion is symmetric.
5. Therefore, the time taken to make an angle of 45° from horizontal can be calculated by the time found in step 3.

Conclusion:
- The time taken for the particle to make an angle of 45° from horizontal can be determined by analyzing the vertical motion and using the initial velocity components.
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A particle is projected from horizontal making an angle 60° with initial velocity 40m/s. Find the time taken to the particle to make an angle 45° from horizontal.plz explain briefly plz....
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