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The ground state of Co2+ ion in CoSO4.7H2O may be regarded as 4T3/2. The entropy of the solid at temperature below 1K is derived almost entirely from electron spin. The molar entropy of the solid at these temperature is ________J/mol-K.(Round off to two decimal places).
    Correct answer is '19.15'. Can you explain this answer?
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    Ground State of Co2+ ion in CoSO4.7H2O

    The ground state of the Co2+ ion in CoSO4.7H2O can be regarded as 4T3/2. This notation indicates that the ground state electronic configuration of the ion is a triplet state with a total spin quantum number of 3/2.

    Entropy Contribution from Electron Spin

    The entropy of a substance at temperatures below 1K is derived almost entirely from the electron spin. In the case of the Co2+ ion, the electron spin can have two possible orientations: spin-up and spin-down. Each orientation has a degeneracy of 2. Therefore, the total degeneracy of the electron spin is 2^2 = 4.

    Molar Entropy Calculation

    To calculate the molar entropy of the solid at temperatures below 1K, we need to consider the degeneracy of the electron spin and the Boltzmann constant.

    The formula to calculate the molar entropy is given by:

    S = R * ln(W)

    Where:
    S = molar entropy
    R = gas constant (8.314 J/mol-K)
    W = degeneracy of the system

    In this case, the degeneracy of the electron spin is 4. Therefore, the molar entropy can be calculated as:

    S = 8.314 * ln(4)
    S = 8.314 * 1.386

    Rounding off to two decimal places, the molar entropy of the solid at temperatures below 1K is 19.15 J/mol-K.

    Conclusion

    The molar entropy of the Co2+ ion in CoSO4.7H2O at temperatures below 1K is 19.15 J/mol-K. This value is calculated based on the degeneracy of the electron spin, which is 4, and the Boltzmann constant. The entropy of the solid at these temperatures is mainly derived from the electron spin contributions.
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    The ground state of Co2+ ion in CoSO4.7H2O may be regarded as 4T3/2. The entropy of the solid at temperature below 1K is derived almost entirely from electron spin. The molar entropy of the solid at these temperature is ________J/mol-K.(Round off to two decimal places).Correct answer is '19.15'. Can you explain this answer?
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    The ground state of Co2+ ion in CoSO4.7H2O may be regarded as 4T3/2. The entropy of the solid at temperature below 1K is derived almost entirely from electron spin. The molar entropy of the solid at these temperature is ________J/mol-K.(Round off to two decimal places).Correct answer is '19.15'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The ground state of Co2+ ion in CoSO4.7H2O may be regarded as 4T3/2. The entropy of the solid at temperature below 1K is derived almost entirely from electron spin. The molar entropy of the solid at these temperature is ________J/mol-K.(Round off to two decimal places).Correct answer is '19.15'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ground state of Co2+ ion in CoSO4.7H2O may be regarded as 4T3/2. The entropy of the solid at temperature below 1K is derived almost entirely from electron spin. The molar entropy of the solid at these temperature is ________J/mol-K.(Round off to two decimal places).Correct answer is '19.15'. Can you explain this answer?.
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