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For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K is
- a)DBr (B = 4.24 cm-1)
- b)DI (B = 3.25cm-1)
- c)CsI (B = 0.0236cm-1)
- d)F35CI (B = 0.516cm-1)
Correct answer is option 'C'. Can you explain this answer?
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For which of the following molecule is the high temperature expression...
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For which of the following molecule is the high temperature expression...
Explanation:
To determine which molecule the high temperature expression for the rotational partition function is valid for, we need to consider the value of the rotational constant (B) for each molecule and compare it to the temperature (T) given.
The high temperature expression for the rotational partition function is given by:
Q_rot = T / B
If T is much greater than B, then the high temperature expression is valid.
Let's analyze each molecule:
a) DBr (B = 4.24 cm-1)
b) DI (B = 3.25 cm-1)
c) CsI (B = 0.0236 cm-1)
d) F35CI (B = 0.516 cm-1)
Comparing T = 40 K to the rotational constant for each molecule:
a) DBr (T/B = 40 K / 4.24 cm-1 = 9.43 K/cm-1)
b) DI (T/B = 40 K / 3.25 cm-1 = 12.31 K/cm-1)
c) CsI (T/B = 40 K / 0.0236 cm-1 = 1694.92 K/cm-1)
d) F35CI (T/B = 40 K / 0.516 cm-1 = 77.52 K/cm-1)
Comparing T to B:
From the calculations above, we can see that for CsI, T/B is the largest value (1694.92 K/cm-1) compared to the other molecules. This indicates that T is much greater than B for CsI, suggesting that the high temperature expression for the rotational partition function is valid for this molecule.
Conclusion:
The high temperature expression for the rotational partition function is valid for CsI (Cesium Iodide) when T = 40 K.
To determine which molecule the high temperature expression for the rotational partition function is valid for, we need to consider the value of the rotational constant (B) for each molecule and compare it to the temperature (T) given.
The high temperature expression for the rotational partition function is given by:
Q_rot = T / B
If T is much greater than B, then the high temperature expression is valid.
Let's analyze each molecule:
a) DBr (B = 4.24 cm-1)
b) DI (B = 3.25 cm-1)
c) CsI (B = 0.0236 cm-1)
d) F35CI (B = 0.516 cm-1)
Comparing T = 40 K to the rotational constant for each molecule:
a) DBr (T/B = 40 K / 4.24 cm-1 = 9.43 K/cm-1)
b) DI (T/B = 40 K / 3.25 cm-1 = 12.31 K/cm-1)
c) CsI (T/B = 40 K / 0.0236 cm-1 = 1694.92 K/cm-1)
d) F35CI (T/B = 40 K / 0.516 cm-1 = 77.52 K/cm-1)
Comparing T to B:
From the calculations above, we can see that for CsI, T/B is the largest value (1694.92 K/cm-1) compared to the other molecules. This indicates that T is much greater than B for CsI, suggesting that the high temperature expression for the rotational partition function is valid for this molecule.
Conclusion:
The high temperature expression for the rotational partition function is valid for CsI (Cesium Iodide) when T = 40 K.
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For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer?
Question Description
For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer?.
For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For which of the following molecule is the high temperature expression for the rotational partition function valid if T = 40K isa)DBr (B = 4.24 cm-1)b)DI (B = 3.25cm-1)c)CsI (B = 0.0236cm-1)d)F35CI (B = 0.516cm-1)Correct answer is option 'C'. Can you explain this answer?.
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