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In an element the complimentary shear stress is always:
  • a)
    Equal in sign
  • b)
    Equal in both magnitude and sign
  • c)
    Equal in magnitude but opposite in sign
  • d)
    None of the above
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In an element the complimentary shear stress is always:a)Equal in sign...
In an element the complimentary shear stress is always equal in magnitude but opposite in sign.
Concept:
Consider a rectangular block ABCD as displayed in following figure. Now assume a set of shear stresses (τ) of opposite direction, as displayed in following figure, is applied over the opposite surfaces of rectangular block i.e. AB and CD.

If we consider the effect of this set of shear stresses (τ) of opposite direction, we can easily say that there will be zero net force acting over the rectangular block but there will be one couple acting over the rectangular block in clockwise direction.
In order to balance the rectangular block, there must be one more couple of similar intensity acting over the rectangular block in opposite direction i.e. in anti-clockwise direction. Therefore, there will be one more set of shear stresses (τ’) of same intensity acting over the rest two opposite surfaces of rectangular block and this set of shear stresses will be termed as complementary shear stress.
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Most Upvoted Answer
In an element the complimentary shear stress is always:a)Equal in sign...
Complimentary shear stress in an element:
In mechanics, shear stress is defined as the force per unit area acting parallel to a given plane within a material. When a material is subjected to shear stress, it deforms by shearing or sliding along the plane.

In a solid element, such as a beam or a plate, shear stress can be resolved into two components - the shear stress acting in one direction and the complimentary shear stress acting in the perpendicular direction. The complimentary shear stress is the shear stress acting in the opposite direction to the original shear stress.

Options:
a) Equal in sign: This option suggests that the complimentary shear stress has the same sign as the original shear stress. However, this is not always the case.

b) Equal in both magnitude and sign: This option suggests that the complimentary shear stress has the same magnitude and sign as the original shear stress. Again, this is not always true.

c) Equal in magnitude but opposite in sign: This option suggests that the complimentary shear stress has the same magnitude as the original shear stress but acts in the opposite direction. This is the correct answer.

Explanation:
When a solid element is subjected to shear stress, the material deforms by shearing along a plane. This shearing causes the material to experience internal forces that resist the deformation. These internal forces can be resolved into two components - one acting in the direction of the original shear stress and the other acting in the perpendicular direction.

The complimentary shear stress is the shear stress acting in the opposite direction to the original shear stress. It has the same magnitude as the original shear stress but acts in the perpendicular direction. This is due to the conservation of momentum and Newton's third law of motion.

For example, if a beam is subjected to shear stress in the horizontal direction, the complimentary shear stress will act in the vertical direction. If the original shear stress is positive, indicating a shearing force in the positive x-direction, the complimentary shear stress will be negative, indicating a shearing force in the negative y-direction.

In conclusion, the complimentary shear stress in an element is always equal in magnitude but opposite in sign to the original shear stress.
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In an element the complimentary shear stress is always:a)Equal in signb)Equal in both magnitude and signc)Equal in magnitude but opposite in signd)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
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