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Two n bit binary strings, S1 and S2 are chosen randomly with uniform probability. The probability that the Hamming distance between these strings (the number of bit positions where the two strings differ) is equal to d is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two n bit binary strings, S1and S2 are chosen randomly with uniform pr...
there n binary bits that can differ but only d should differ in this case
ways of choosing these d bits = nCd probability of d bits differ but, n - d bits do not differ = (1/2)d(1/2)(n - d)
no of ways = nCd/2n
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Two n bit binary strings, S1and S2 are chosen randomly with uniform probability. The probability that the Hamming distance between these strings (the number of bit positions where the two strings differ) is equal to d isa)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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