Due to a point charge potential and field at a point A are 7 and 3 respectively.And at point B is less than 3.Now magnitude of charge is tripled if electric field at B now becomes 3. What is the potential at B now? Just give me a complete solution of this ques pls.?

Question

Answer

Bro go on Google..!
sol.n mil hi jayenga...!

Answer

Understanding the Problem
We have two points, A and B, influenced by a point charge. The potential and electric field at point A are given as follows:
- Potential at A (VA) = 7 V
- Electric Field at A (EA) = 3 N/C
At point B, the potential is less than the potential at A, and the electric field is initially less than 3 N/C. When the charge is tripled, the electric field at B becomes 3 N/C.
Key Concepts
- The potential (V) due to a point charge is given by V = k * Q / r, where k is the Coulomb's constant, Q is the charge, and r is the distance from the charge.
- The electric field (E) is given by E = k * Q / r^2.
Initial Conditions at Point B
1. Since the electric field at B is initially less than 3 N/C, let’s denote it as E_B < 3='' />
2. The potential at B (VB) is less than VA, so VB < 7='' />
Effect of Tripling the Charge
When the charge is tripled, the new electric field at point B becomes:
- New Electric Field at B (E'_B) = 3 N/C.
Using the relationship of electric field, we can write:
E'_B = k * (3Q) / r^2 = 3 N/C.
This implies that the distance (r) from the point charge to point B has not changed.
Calculating the New Potential at Point B
The new potential at point B after tripling the charge can be calculated as:
V'_B = k * (3Q) / r.
Since we know the original potential at point B was less than 7 V, we can consider the change:
- Original Potential (VB) < 7='' />
- New Potential (V'_B) = 3 * Original Potential (VB) (due to tripling the charge)
Thus, we can infer:
V'_B = 3 * (VB) < 3='' *='' 7='21' />
Since the new electric field at B is now 3 N/C, it confirms that the potential at B must have increased significantly, leading to:
Final Answer
The potential at point B now is 21 V.

Similar JEE Doubts

The electric field and the electric potential at a point are E and V respectively . a. if E=0 ,V must be zero b. If V=0 ,E must be zero c. If E is Not equals To zero , v cannot be zero d. If V is Not equals To zero , E cannot be zero?

An electric dipole has the magnitude of its charge as q, and its dipole moment is p. It is placed in a uniform electric field E. If its dipole moment is along the direction of the field, then force acting on it and its potential energy are respectively

A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,

The grid (each square of 1m*1m ) , represent a region in space containing a uniform electric field. If potentials at point O, A, B, C, D, E, F, G,A, and H are respectively 0,-1,-2,1,2,0,-1,1and 0 volts, find the electric field intensity in vector form?

Top Courses for JEEView all

Physics for JEE Main & Advanced

Mock Tests for JEE Main and Advanced 2025

Mathematics (Maths) for JEE Main & Advanced

Chemistry for JEE Main & Advanced

Chapter-wise Tests for JEE Main & Advanced

Top Courses for JEE

Top Courses for JEE

Suggested Free Tests

Related Content

JEE Courses

Mock Test Series

Past Year Papers

Additional Courses

Company